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3 years ago

Which value represents a horizontal shift (left and right) in the following function y=a*sin(bx-c)+d

Mathematics

1 answer:

grigory [225]3 years ago

5 0

The value is C because it represents the shift

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Which of the following is NOT equal to sin pi/3

Yanka [14]

Answer:

D) $sin(\frac{4\pi }{3} ) = sin(\pi +\frac{\pi }{3} ) = -sin\frac{\pi }{3}$

Step-by-step explanation:

$sin(\frac{2\pi }{3} ) = sin ( \pi - \frac{\pi }{3} ) = sin\frac{\pi }{3}$

$cos (\frac{\pi }{6} ) = cos ( \frac{\pi }{2} - \frac{\pi }{3} ) = sin(\frac{\pi }{3})$

$cos (\frac{11\pi }{6} ) = cos ( \frac{3\pi }{2} + \frac{\pi }{3} ) = sin(\frac{\pi }{3})$

$sin(\frac{4\pi }{3} ) = sin(\pi +\frac{\pi }{3} ) = -sin\frac{\pi }{3}$

8 0

3 years ago

A park is rectangular with a length of ⅔ miles. If the area of the park is 3/9 square miles, what is the width?

Zielflug [23.3K]

Answer:

Area of the rectangular park = 2/3 square mile

Let us assume the width of the rectangular park = x

Then

The length of the rectangular park = 2 2/3 * x mile

= 8x/3 mile

Then

Area of the rectangular park = Length * Width

2/3 = (8x/3) * x

2/3 = 8x^2/3

(2 * 3)/3 = 8x^2

2 = 8x^2

x^2 = 2/8

x^2 = 1/4

x^2 = (1/2)^2

x = 1/2

So the width of the park is 1/2 feet.

Step-by-step explanation:

Brainliest would be nice

4 0

3 years ago

Read 2 more answers

15) The diameter of a cylinder is 12 and height is 11. Find the surface area of the figure.

kirza4 [7]

Answer:

A=640.88

Step-by-step explanation:

if the diameter is 12, the radius , r=12/2=6

we have r=6, h=11

Surface area, A= 2πrh+2π r^2

A=2*3.14*6*11+2*3.14*(6)^2=640.88

7 0

3 years ago

I don’t understand this at all please help

Deffense [45]

Answer:

You need 10 of those numbers to be whole numbers, decimals, or fractions (THESE ARE RATIONAL)

You need the other 10 of those numbers to radicals, or numbers similar to pi (THESE ARE IRRATIONAL)

Step-by-step explanation:

4 0

3 years ago

What is the solution?

Ilia_Sergeevich [38]

Answer:

A. { $3+7i,3-7i$ }

Step-by-step explanation:

The given equation is $x^2-6x+58=0$

Use the quadratic formula with a=1,b=-6 and c=58

Recall the quadratic formula;

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

We substitute the given values to get;

$x=\frac{--6\pm \sqrt{(-6)^2-4(1)(58)} }{2(1)}$

$x=\frac{6\pm \sqrt{36-232} }{2}$

$x=\frac{6\pm \sqrt{-196} }{2}$

Recall that;

$\sqrt{-1}=i$

$x=\frac{6\pm 14i}{2}$

$x=3\pm 7i$

$x=3+7i$ or $x=3-7i$

8 0

3 years ago

Read 2 more answers