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3 years ago

Which value represents a horizontal shift (left and right) in the following function y=a*sin(bx-c)+d

Mathematics

1 answer:

grigory [225]3 years ago

5 0

The value is C because it represents the shift

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I need help on two questions!

Inessa05 [86]

1) Answer: $\frac{x^{2}}{100} +\frac{y^{2}}{4} = 1$

<u>Explanation:</u>

The equation of an ellipse is: $\frac{(x-h)^{2}}{a^{2}} +\frac{(y-k)^{2}}{b^{2}} = 1$ ; where (h, k) is the center, "a" is the x-radius, and "b" is the y-radius.

Center Radius

x-axis: (10 + -10)/2 = 0 10 - 0 = 10

h = 0 a = 10

y-axis: (2 + -2)/2 = 0 2 - 0 = 2

k = 0 b = 2

Now, input the values into the equation:

$\frac{(x-0)^{2}}{10^{2}} +\frac{(y-0)^{2}}{2^{2}} = 1$

$\frac{x^{2}}{100} +\frac{y^{2}}{4} = 1$

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2) Answer: $\frac{x^{2}}{1} +\frac{(y+2)^{2}}{4} = 1$

<u>Explanation:</u>

Vertices are: (0, 1) and (0, -5) ------> x-values are the same, y = 1, -5

Covertices are: (-1, -2) and (1, -2) ----> y-values are the same, x = -1, 1

Center Radius

x-axis: (-1 + 1)/2 = 0 1 - 0 = 1

h = 0 a = 1

y-axis: (1 + -5)/2 = -2 1 - (-2) = 3

k = -2 b = 3

Now, input the values into the equation:

$\frac{(x-h)^{2}}{a^{2}} +\frac{(y-k)^{2}}{b^{2}} = 1$

$\frac{(x-0)^{2}}{1^{2}} +\frac{(y-(-2))^{2}}{3^{2}} = 1$

$\frac{x^{2}}{1} +\frac{(y+2)^{2}}{9} = 1$

3 0

4 years ago

Add:(3x2 - 5x + 6) + (9 - 8x - 4x2)

finlep [7]

You can see by the image how did I get the answer

3 0

4 years ago

What is the measurement of angle C? Part C

Genrish500 [490]

No idea

Forgot picture

6 0

3 years ago

Read 2 more answers

In how many ways can 4 people sit next to each other in a stadium row

Viktor [21]

Answer:

They can sit next to each other in 24 different ways.

Step-by-step explanation:

In order to solve this problem, use the factorial function (!).

4! = 4 * 3 * 2 * 1 = 24

8 0

3 years ago

Given y = 4x + 3, what effect does changing the equation to y = 4x - 3 have on the y-intercept?

Art [367]

Answer:

The y-intercept changes from (0, 3) to (0, -3)

Step-by-step explanation:

The y-intercept refers to the point where the graph of a function crosses or intersects with the y-axis. At this point, the value of x is usually 0.

Substitute x = 0 in both equations to determine how the y-intercept changes;

The original equation is given as y = 4x + 3,

when x = 0; y = 4(0) + 3 = 3

The y-intercept is thus (0, 3)

The new equation is given as y = 4x - 3

when x = 0; y = 4(0) - 3 = -3

The y-intercept is thus (0, -3)

Therefore, the y-intercept changes from (0, 3) to (0, -3)

3 0

4 years ago