L= length= 1 1/2 yards
A= area= 3 1/2 yards^2
w= width
Area= length * width
plug in numbers you know
3 1/2= (1 1/2)(w)
convert to improper fractions
(3*2+1)/2= ((1*2+1)/2)(w)
7/2= 3/2w
divide both sides by 3/2
7/2 ÷ 3/2= w
to divide fractions, multiply by the reciprocal/inverse of 3/2
7/2 * 2/3= w
(7*2)/(2*3)= w
14/6= w
reduce by 2
7/3= width as improper fraction
OR
2 1/3= width as mixed fraction
ANSWER: The width should be 2 1/3 yards wide (or 7/3 yards wide).
Hope this helps! :)
Answer:
B
Step-by-step explanation:
The unit vector is given by the following formula:
a '= (a) / (lal)
Where,
a: vector a
lal: Vector module a
We are looking for the module:
lal = root ((- 15) ^ 2 + (8) ^ 2)
lal = 17
Same direction:
a = -15i + 8j
The unit vector is:
a '= (1/17) * (- 15i + 8j)
Opposite direction:
a = 15i - 8j
The unit vector is:
a '= (1/17) * (15i - 8j)
Answer:
a unit vector that has the same direction as the vector a is:
a '= (1/17) * (- 15i + 8j)
a unit vector that has the opposite direction of the vector a is:
a '= (1/17) * (15i - 8j)
Y = -2x + 6....so we sub in -2x + 6 for y in the other equation
3y - x + 3 = 0
3(-2x + 6) - x + 3 = 0
-6x + 18 - x + 3 = 0
-7x + 21 = 0
-7x = -21
x = -21/-7
x = 3
now we sub 3 in for x in either of the original equations to find y.
y = -2x + 6
y = -2(3) + 6
y = -6 + 6
y = 0
so ur solution is : (3,0)
