Answer:
The vertices of triangle A'B'C' produced by (x, y) → (x+5, y-2) will be:
Step-by-step explanation:
Given the vertices of an original triangle ΔABC such that
As the rule of translation is given by
Translation: (x, y) → (x+5, y-2)
So, after the translation the vertices of the original triangle ΔABC will be translated as:
A = (3, 0) → (x+5, y-2) ⇒ (3+5, 0-2) = A'(8, -2)
B = (3, 2) → (x+5, y-2) ⇒ (3+5, 2-2) = B'(8, 0)
C = (0, -3) → (x+5, y-2) ⇒ (0+5, -3-2) = C'(5, -5)
Therefore, the vertices of triangle A'B'C' produced by (x, y) → (x+5, y-2) will be:
