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Y_Kistochka [10]
3 years ago
14

Determine the missing information in the paragraph proof. Given: Line PQ contains points (w, v) and (x, z) and line P'Q' contain

s points (w + a, v + b) and (x + a, z + b). Lines PQ and P'Q' are parallel. Prove: Parallel lines have the same slope. Since slope is calculated using the formula , the slope of both lines is equivalent to ________. It is given that the lines are parallel, and we calculated that the slopes are the same. Therefore, parallel lines have the same slopes.
Mathematics
2 answers:
statuscvo [17]3 years ago
7 0

Answer:

The answer is A) v-z / w-x


labwork [276]3 years ago
3 0
Slope = change in y / change in x
Slope of PQ = (z - v) / (x - w)

Slope of P'Q' = (z + b - (v + b)) / ((x + a) - (w + a))
Slope of P'Q' = (z - v) / (x - w)

The slopes of both lines are equivalent to 
(z - v) / (x - w)
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  AA similarity theorem

Step-by-step explanation:

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11111nata11111 [884]

ANSWER

y=\frac{2}{3}x+\frac{4}{3}

EXPLANATION

We want to find the equation of the straight line given on the graph.

The general form of a linear equation is given as:

y=mx+b

where m = slope; b = y-intercept

To find the slope, we apply the formula for slope:

m=\frac{y_2-y_1}{x_2-x_1}

where (x1, y1) and (x2, y2) are two points on the line

Let us pick (1,2) and (4,4)

Therefore, the slope is:

m=\frac{4-2}{4-1}=\frac{2}{3}

To find the equation, we now apply the point-slope formula:

y-y_1=m(x-x_1)

Therefore, we have that the equation of the line is:

\begin{gathered} y-2=\frac{2}{3}(x-1) \\ y-2=\frac{2}{3}x-\frac{2}{3} \\ y=\frac{2}{3}x-\frac{2}{3}+2 \\ y=\frac{2}{3}x+\frac{4}{3} \end{gathered}

That is the equation of the line.

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