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Vesna [10]
3 years ago
6

11.3x + 7.2 = 86.3 solve

Mathematics
2 answers:
galben [10]3 years ago
7 0
11.3x = 86.3 - 7.2
11.3x = 79.1
79.1/11.3 = x
x = 7
Ilia_Sergeevich [38]3 years ago
4 0
11.3x+7.2-7.2=86.3-7.2
11.3x=79.1
11.3x/11.3=79.1/11.3

x=7

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4. In football, the team that has the ball has fourchances to gain at least ten yards. If they don't gain at least ten yards, th
jok3333 [9.3K]

Answer:

A , C, D

Step-by-step explanation:

Check A:

8 - 3 + 4 + 21 = 30         30 > 10 , so they keep the ball

Check B:

30 - 7 - 8 - 12 = 3          3 < 10 , so they don't keep the ball

Check C:

2 + 16 - 5 - 3 = 10         10 = 10 , so they keep the ball

Check D:

5 - 2 + 20 - 1 = 22       22 > 10 , so they keep the ball

Check E:

20 - 3 - 13 + 2 = 6         6 < 10 , so they don't keep the ball

If my answer is incorrect, pls correct me!

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8 0
3 years ago
Read 2 more answers
Please help me with my math
boyakko [2]

Answer:

x = 115

z = 27

Step-by-step explanation:

x + 65 = 180 (same side interior angles)

x = 115

x = 3z +34 (alternate interior angles)

115 = 3z + 34

3z = 81

z = 27

5 0
2 years ago
Read 2 more answers
What is the value of x?
gavmur [86]

x=23

a²+b²=c²

25+144=169

the square root of 169 is 13

add 10 to get x

23

4 0
3 years ago
Solve 30kx – 6kx = 8 for x. A. B. C. x = 3k D.
NemiM [27]

Answer:

x = 1 /3k

Step-by-step explanation:

30kx – 6kx = 8

24kx = 8

x = 8 / 24k

x = 1 /3k   (answer).


8 0
3 years ago
Given that log_{a}(3) = 0.477 and
kipiarov [429]

Given:

\log_{a}(3) = 0.477,\log_{a}(5) = 0.699

To find:

The value of \log_{a}(0.6).

Solution:

We need to find the value of:

\log_{a}(0.6)

It can be written as

\log_{a}(0.6)=\log_a\left(\dfrac{6}{10}\right)

\log_{a}(0.6)=\log_a\left(\dfrac{3}{5}\right)

By using the property of logarithm, we get

\log_{a}(0.6)=\log_a(3)-\log_a(5)        [\because \log \dfrac{a}{b}=\log a-\log b]

\log_{a}(0.6)=\log_a(3)-\log_a(5)

On substituting the given values, we get

\log_{a}(0.6)=0.477-0.699

\log_{a}(0.6)=-0.222

Therefore, the values of \log_a(0.6) is -0.222.

6 0
3 years ago
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