List what you are thankful for! (It's Thanksgiving! Answer if you bake! Or if you like cakes pies cookies and treats!!! )

Mathematics

2 answers:

pishuonlain [190]3 years ago

7 0

Answer:

I'm thankful for everything :3

I do not know how to bake but I love cookies UvU

Step-by-step explanation:

IRINA_888 [86]3 years ago

7 0

Answer:

My family!

Step-by-step explanation:

I am baking cheesecake

You might be interested in

NEED HELP FAST FOR TEST!!!

ozzi

I'm not just going to give you that answer, i'm going to teach you how to do it for yourself. this is a function. what you do first is look at what the question is asking you, it's asking you to solve the function, when the value of x are as follows: -2, 1, 2. start with the easiest number, 1, and plug it in for x in each equation.

5• (1)^2 + 0
10• (1)^2 + 0

then set each equation equal to zero

5 • (1)^2 + 0 = 0
10 • (1)^2 + 0 = 0

now solve each equation. make sure the value value you get for the first equation is a negative number, because the question demands that by giving you "x<1"

complete the same steps for each other value to get the answers. hope this helps.

5 0

3 years ago

I need the answer to

Vesnalui [34]

Answer:

I think its B

Hope this helps

8 0

3 years ago

Please help I have limited time.

dmitriy555 [2]

Answer:

Answer is B.

Hope this helps.

8 0

3 years ago

The diagram shows a 5 cm x 5 cm x 5 cm cube.

mylen [45]

Answer:

~8.66cm

Step-by-step explanation:

The length of a diagonal of a rectangular of sides a and b is

$\sqrt{a^2+b^2}$

in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:

$\sqrt{\sqrt{a^2+b^2}^2 + c^2} = \sqrt{a^2+b^2+c^2}$

Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths $a_1, a_2, a_3, \ldots, a_n$ is