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3 years ago

Multiplication is a faster way to do repeated

Mathematics

2 answers:

Sedbober [7]3 years ago

6 0

Answer:

Additions.

Step-by-step explanation:

Multiplication is equivalent to repeated additions and is faster, especially if the numbers are large.

A simple example is 2 * 3 = 2 + 2 + 2.

Paladinen [302]3 years ago

3 0

Answer:

Addition.

Step-by-step explanation:

Multiplication is a faster way to do repeated addition.

For example, lets say you would add 10 fifteen's together. Addition would make it:

15 + 15 + 15 + 15 + 15 + 15 + 15 + 15 + 15 + 15

= 30 + 30 + 30 + 30 + 30

= 60 + 60 + 30

= 120 + 30

= 150

However, when multiplying:

15 x 10 = 150

As you can tell, multiplication makes it so there are less steps, and is less time consuming.

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Answer:

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Step-by-step explanation:

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2 years ago

20a + 158 +6c = 20 (6) + 15 (4) + 6(8)<br> +<br> ?<br> +<br> ?

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Step-by-step explanation:

20a + 158+6c=you will expand the brackets

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3 years ago

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Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

In △ABC, AD and BE are the angle bisectors of ∠A and ∠B and DE ║ AB . Find the length of DE if perimeter of ABDE is 30 cm and AB

-BARSIC- [3]

Answer:

DE = 6 cm

Step-by-step explanation:

Let DE = x cm.

Since DE is parallel to AB therefore by the alternate interior angles theorem, m∠BAD = m∠ADE and m∠ABE = m∠DEB ............(1)

As AD is an angle bisector of ∠A, therefore m∠EAD = m∠DAB ; Since BE is an angle bisector of ∠B ⇒ m∠ABE = m∠EBD.

Therefore, from (1) We get , m∠EAD = m∠ADE and m∠EBD = m∠BED.

So, the triangles ADE and EDB are then isosceles with AE = ED and ED = DB.

So AE = DE = DB = x, and since the perimeter of ABDE is 30 cm, then

12 + x + x + x = 30

⇒ 12 + 3x = 30

⇒ x = 6

Hence, the length of DE is 6 cm.

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3 years ago

Read 2 more answers

Can somebody please explain and answer this for me? I really don't get it.

Tcecarenko [31]

Answer:

Results can be $(-\frac{1}{3} )^5$

Step-by-step explanation:

-The solution for this question:

$(-\frac{1}{3} )^5$ is equal to $(-\frac{1}{3})$ × $(-\frac{1}{3})$ × $(-\frac{1}{3})$ × $(-\frac{1}{3})$ × $(-\frac{1}{3})$

-The calculation for $(-\frac{1}{3} )^5$ :

$(-\frac{1}{3} )^5 = -\frac{1}{243}$

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3 years ago