Hope this helps! The slope of the line passing through
(
2
,
7
)
and
(
0
,
−
5
)
is
m
=
y
2
−
y
1
x
2
−
x
1
=
−
5
−
7
0
−
2
=
−
12
−
2
=
6
.
(
2
,
7
)
and
(
0
,
−
5
)
is
m
=
y
2
−
y
1
x
2
−
x
1
=
−
5
−
7
0
−
2
=
−
12
−
2
=
6
.
Multiplication is a faster way to do repeated
2 answers:
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Answer:
B. A rectangle, 4 in by 3 in
Step-by-step explanation:
The foam has the shape of a cuboid with base of 10 in by 4 in and height of 3 in.
The foam has a front elevation of a rectangle with dimension of 4 in by 3 in. It has a left elevation of dimension 10 in by 3 in and a plan of dimension 10 in by 4 in.
If the foam is cut along the red line, the exposed face would be the same as the shape of the front elevation. Hence the shape of the cross section would be a rectangle with dimension of 4 in by 3 in.
Answer: The correct statements are
The GCF of the coefficients is correct.
The variable c is not common to all terms, so a power of c should not have been factored out.
David applied the distributive property.
Step-by-step explanation:
GCF = Greatest common factor
1) GCF of coefficients : (80,32,48)
80 = 2 × 2 × 2 × 2 × 5
32 = 2 × 2 × 2 × 2 × 2
48 = 2 × 2 × 2 × 2 × 3
GCF of coefficients : (80,32,48) is 16.
2) GCF of variables :()
= b × b × b × b
= b × b
=b × b × b × b
GCF of variables :() is
3) GCF of and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.
4)
David applied the distributive property.