CAN SOMEBODY PLLZZZZ HELP ME WITH THE QUESTION BELOW AND HOW TO SOLVE QUESTIONS LIKE THIS, IM STUDYING FOR A MATH TEST PLLLZZ!!!
Thank You!
1 answer:
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We have the formula to compute the probability of having exactly k successed over n trials, given a probability p of success (and implicitly a probability 1-p of failure), which is
Now, the probability of at least 3 successes is the union of the following event: exactly three successes,exactly four successes and exactly five successes.
We can compute their probability and sum them:
So, the answer is about 36.79%
Check the table attached.
The first coordinates of each pair represent the 1.roll, and the second coordinates the 2nd, roll.
All the possible outcomes are {(1, 1), (1, 2).... (6, 5), (6, 6)}, a total of 36, as can be seen in the table.
Each outcome has a chance of 1 out 36 total possible outcomes of occurring.
So the probability is 1/36=0.02778
The first coordinates of each pair represent the 1.roll, and the second coordinates the 2nd, roll.
All the possible outcomes are {(1, 1), (1, 2).... (6, 5), (6, 6)}, a total of 36, as can be seen in the table.
Each outcome has a chance of 1 out 36 total possible outcomes of occurring.
So the probability is 1/36=0.02778