Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
Answer: -8/3
Step-by-step explanation:
Multiplying a positive and a negative equals negative: (+)•(-)=(-)
y= - 2/3•4
Y= -8/3
SQRT each individual bit: 4 and
and 9 and
5/12 is your answer to 5/6 times 1/2
Answer:
m = E/c²
Step-by-step explanation:
E = mc²
mc² = E
Divide both sides by c².
m = E/c²
