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zmey [24]
3 years ago
14

Solve tan x =cot x for 0 < x < pi

Mathematics
1 answer:
NeX [460]3 years ago
5 0

tan(<em>x</em>) = cot(<em>x</em>)

tan(<em>x</em>) = 1 / tan(<em>x</em>)

tan²(<em>x</em>) = 1

tan²(<em>x</em>) - 1 = 0

(tan(<em>x</em>) - 1) (tan(<em>x</em>) + 1) = 0

tan(<em>x</em>) - 1 = 0   or   tan(<em>x</em>) + 1 = 0

tan(<em>x</em>) = 1   or   tan(<em>x</em>) = -1

<em>x</em> = <em>π</em>/4 + <em>nπ</em>   or   <em>x</em> = -<em>π</em>/4 + <em>nπ</em>

where in both cases, <em>n</em> is any integer.

In the interval 0 < <em>x</em> < <em>π</em>, we get solutions:

• <em>x</em> = <em>π</em>/4 from the first family (when <em>n</em> = 0)

• <em>x</em> = 3<em>π</em>/4 from the second family (when <em>n</em> = 1)

So the equation has solutions <em>x</em> = <em>π</em>/4 or <em>x</em> = 3<em>π</em>/4.

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========================================================

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