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3 years ago

5

Jackie bought 20 lb. of dog food. The dog food is packaged in 2, 4, and 8 lb. bags. How many bags of each size would Jackie have

bought?

1 answer:

Len [333]3 years ago

8 0

Answer: 10 bags that weigh 2 lb.

5 bags that weigh 4 lb.

2.5 bags that weigh 8 lb.

Hope this helps.

Step-by-step explanation:

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4 years ago

Pls solve. Showing your work is suggested.

allsm [11]

Answer:

Part 3) Miguel scored 29 points and Alonzo scored 25 points

Part 4) Morgan's age is 14 1/2 years and Mr Santos' age is 29 1/2 years

Step-by-step explanation:

Part 3) Let

x ----> the number of points that Miguel scored

y ---> the number of points that Alonzo scored

we know that

$x+y=54$ ----> equation A

$x=y+4$ ----> equation B

substitute equation B in equation A and solve for y

$(y+4)+y=54\\2y=54-4\\2y=50\\y=25$

Find the value of x

$x=25+4=29$

the solution is the point (29,25)

That means ----> Miguel scored 29 points and Alonzo scored 25 points

Part 4) Let

x ----> Morgan's age

y ---> Mr Santos' age

we know that

$x+y=44$ -----> equation A

$x=y-15$ ----> equation B

substitute equation B in equation A and solve for y

$(y-15)+y=44\\2y=44+15\\2y=59\\y=29.5$

Find the value of x

$x=29.5-15=14.5$

the solution is the point (14.5,29.5)

That means ----> Morgan's age is 14 1/2 years and Mr Santos' age is 29 1/2 years

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3 years ago

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larisa86 [58]

Answer:

60°, 120°

Step-by-step explanation:

$\frac{ {tan}^{2}x }{2} - 2 {cos}^{2}x = 1 \\ \\ \frac{ {tan}^{2}x - 4{cos}^{2}x }{2} = 1 \\ \\ {tan}^{2}x - 4{cos}^{2}x = 2 \\ \\ \frac{{sin}^{2}x}{{cos}^{2}x} - 4{cos}^{2}x = 2 \\ \\ \frac{{sin}^{2}x - 4{cos}^{4}x}{{cos}^{2}x} = 2 \\ \\ {sin}^{2}x - 4{cos}^{4}x = 2{cos}^{2}x \\ \\ 4{cos}^{4}x + 2{cos}^{2}x - {sin}^{2}x = 0 \\ \\ 4{cos}^{4}x + 2{cos}^{2}x + {cos}^{2}x - 1= 0 \\ \\ 4{cos}^{4}x + 3{cos}^{2}x - 1= 0 \\ \\ 4{cos}^{4}x + 4{cos}^{2}x - {cos}^{2}x - 1= 0 \\ \\4{cos}^{2}x({cos}^{2}x + 1) - 1({cos}^{2}x + 1) = 0 \\ \\ ({cos}^{2}x + 1)(4{cos}^{2}x - 1) = 0 \\ \\ ({cos}^{2}x + 1) = 0 \: or \: (4{cos}^{2}x - 1) = 0 \\ \\ {cos}^{2}x = - 1 \: or \: 4{cos}^{2}x = 1 \\ \\ {cos}x = \sqrt{ - 1} \: which \: is \: not \: possible \\ \therefore \: {cos}^{2}x = \frac{1}{4} \\ \\ \therefore \: {cos}x = \pm\frac{1}{2} \\ \\ \therefore \: {cos}x = \frac{1}{2} \: or \: {cos}x = - \frac{1}{2} \\ \\ \therefore \: {cos}x = {cos}60 \degree \: or \: {cos}x = {cos}120 \degree \\ \\ \therefore \:x = 60 \degree \: \: or \: \: x = 120 \degree$

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