

Consequently, t<span>he limit of

as x approaches infinity is

.
In other words,

approaches the line y=x,
</span><span>
so oblique asymptote is y=x.
I'm Japanese, if you find some mistakes in my English, please let me know.</span>
Use this systems of equations to solve:
x = first antifreeze
y = second antifreeze

Isolate y.
x + y = 15
Subtract x from both sides.
y = -x + 15
Substitute y into the other equation.
.2x + .12(-x + 15) = .18(15)
Simplify.
.2x - .12x + 1.8 = 2.7
Subtract 1.8 from both sides.
.08x = .9
Divide both sides by .08
x = 11.25
Substitute x in the equation that we isolated y in.
y = -11.25 + 15
y = 3.75
11.25 L of the first antifreeze and 3.75 L of the second.
Answer:
19.34cm
Step-by-step explanation:
Rigth Angled triangle
use SOHCAHTOA
Cos°=adj/hyp
Cos 71=6.3/BC
BC=6.3/COS 71
COS 71°= 0.3256
BC=6.3/0.3256
BC= 19.34cm