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Murrr4er [49]
3 years ago
12

Put these algebraic expressions into verbal expressions and Coefficient/Variables

Mathematics
1 answer:
Igoryamba3 years ago
6 0

Answer:

1. 2 subtracted from x² equals 5

2. The product of x and 5 subtracted from 3 is -10

Step-by-step explanation:

1.) x² - 2 = 5

2 subtracted from x² equals 5

2.) 3 - 5x = -10

The product of x and 5 subtracted from 3 is -10

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5
SOVA2 [1]

Answer:

The shortest whole number height that will hold the fishing pole is 5 feet.

Step-by-step explanation:

Please see the attached files for details

4 0
3 years ago
Re write the statement 19+7 divided by 2-5 by including one pair of brackets to make the total equal to 8
Oksanka [162]

Answer:

The solution is given below:

Step-by-step explanation:

The computation is shown below:

= 19 +  7 divided by 2 - 5

= (19 + 7) ÷ (2) - 5

= 26 ÷ 2 - 5

= 13 - 5

= 8

Hence, after solving this the value would be 8

Therefore it is equal to the 8

Hence, the given statement is true

6 0
3 years ago
In a survey, 150 people were asked if they smoke and whether or not they exercise regularly (more than twice a week). The result
s2008m [1.1K]
(a) 28%

(b) 24%

When calculating the total amount of people it come out to 150.

According to the table 42 people smoke. 42/150 is 28%

According to the table 36 people exercise regularly. 36/150 is 24%
7 0
3 years ago
Suppose an isosceles triangle ABC has A = 45° and b = c = 4. What is the length of a^2?
Mila [183]
Since b = c, the angles B and C are congruent.
180 - 45 = 135
135/2 = =67.5

A = 45
B = 67.5
C = 67.5
a = ?
b = 4
c = 4

Since we know two sides and all three angles, we can use the law of sines to find a.

b/sin B = a/sin A

4/(sin 67.5) = a/(sin 45)

a = 4(sin 45)/(sin 67.5)

a^2 = (4(sin 45)/(sin 67.5))^2

a^2 = 9.37
4 0
3 years ago
Please Help me!!!
drek231 [11]

Step-by-step explanation:

The displacement of a particle d (in km) as a function of time t (in hours) is given by :

d=2t^3+5t^2-3

Displacement at t = 4 hours,

d(4)=2(4)^3+5(4)^2-3=205\ km

Velocity of particle is given by :

v=\dfrac{dd}{dt}\\\\v=\dfrac{d(2t^3+5t^2-3)}{dt}\\\\v=6t^2+10t

Velocity at t = 4 hours,

v=6(4)^2+10(4)=136\ km/h

Acceleration of the particle is given by :

a=\dfrac{dv}{dt}\\\\a=\dfrac{d(6t^2+10t)}{dt}\\\\a=12t+10

At t = 4 hours,

a=12(4)+10=58\ km/h^2

Therefore, the displacement, velocity and acceleration at t = 4 hours is 205 km, 136 km/h and 58 km/h² respectively.

7 0
3 years ago
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