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3 years ago

11

How many elements are in the set {A,B,C}?

2 answers:

Andrew [12]3 years ago

7 0

Three I think. Might be wrong

ElenaW [278]3 years ago

6 0

Answer:

There are 3 elements in the set.

Step-by-step explanation:

Given set,

{A, B, C}

∵ Set is the collection of defined distinct objects,

These objects are called elements of the set,

We have given a set in which A, B, C are present thus they must be distinct,

So, by the above definition,

The given set has three elements.

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Aria is going to a carnival that has games and rides. Each game costs $3.50 and each ride costs $5. Aria spent $42 altogether at

slavikrds [6]

$Let \: x \: be \: the \: number \: of \: games \: she \: played\Rightarrow the \: number \: of \: rides \: she \: went: x+5 \\ We \: have \: an \: equation:3.5x + 5(x + 5) = 42 \\ \Leftrightarrow 3.5x + 5x + 25 = 42\Leftrightarrow 8.5x = 17\Leftrightarrow x = 2 \Leftrightarrow x + 5 = 2 + 5 = 7\\ \Rightarrow She \: played \: 2 \: games \: and \: went \: on \: 7 \: rides$

7 0

4 years ago

Read 2 more answers

HELP ASAP!! 10 POINTS!

Lilit [14]

Answer:

1. -13

2. 8

Step-by-step explanation:

39 / -13 = 3

-64 / 8 = -8

Hope this helps!!!

3 0

3 years ago

1/4+(-3/4)= ?<br>(Sorry I didn't have a calculator)

IrinaVladis [17]

The answer would be
-1/2

or in decimal form
-0.5

hope this helps :)

3 0

3 years ago

Which shows a set of three equivalent decimals?

Bezzdna [24]

The best choice is A)

when you add a zero, it does not count on a decimal, so,

1.9, 1.90, 1.900.

8 0

3 years ago

Read 2 more answers

For the case of 5-item order, how many different ways are there to place an order? For Each case, list the number of wheels that

Nata [24]

Answer:

Follows are the description of the given point:

Step-by-step explanation:

Please find the correct question in the attached file.

In point A:

An order of 5 items shall be placed in a total of 6 different ways.

(w for cars and ts and tricycles to be used)

$\to 5w=20 wheels\\\\\to 4w+1t= 19 wheels\\\\\to 3w+2t=18 wheels\\\\\to 2w+3t=17 wheels\\\\\to 1w+4t= 16 wheels\\\\\to 5t=15 wheels\\\\$

In point B:

2 waggons so more tyres would be required if they ordered any more waggons.

$work: \\\\ \to 2 \times 4=8 \\\\ \to 3 \times 3=9 \\ \\ \to 8+9=17$

8 0

3 years ago