The problem ask to calculate the slope of the line tangent to a circle O at point A if the radius of the circle is 2.5. So based on the problem the tangent line formed a right angle so it means that the slope is also 2.5 and the answer is letter B. 2.5
Answer:
y= 18
Step-by-step explanation:
Answer:
Same side: 4, 1.5, 5/3, 0.2
Opposite side: -5, -1/4
Step-by-step explanation:
We know that dilation caused by a positive factor leads to the object being on the same side and dilation caused by a negative factor leads to the object being on the opposite side. Therefore, the dilation caused by positive numbers 4, 1.5, 5/3, 0.2 will lead to object being on the same side. And dilation caused by a negative numbers -5 and -1/4 will lead to object being reflected to the opposite side
Answer:
titutex=cos\alp,\alp∈[0:;π]
\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+
1−x
2
∣=
2
(2x
2
−1)\Leftright∣cos\alp+sin\alp∣=
2
(2cos
2
\alp−1)
\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N
2
cos(\alp−
4
π
)∣=N
2
cos(2\alp)\Right\alp∈[0;
4
π
]∪[
4
3π
;π]
1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;
4
π
]
\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−
4
π
)=cos(2\alp)…
2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[
4
3π
;π]
\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−
4
π
)=cos(2\alp)…
1
Top
Display
let's common be "x" 8x add 5x equal to 13 x now x equal to 26 devise 13 equal to 2,. so ans is 2