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3 years ago

11

A store donates 453 laptops to a school. The laptops are divided evenly among the 23 classrooms

2 answers:

Alex73 [517]3 years ago

4 0

19.2 is the answer to your question

masya89 [10]3 years ago

3 0

If the last word is "library", there is 16 laptops in the library.
453/23=19 and 16/23
16 is the remainder, so the answer is 16 laptops

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Which of the following functions gives the length of the base edge, a(V), of a right square pyramid that is 8 inches tall as a f

BARSIC [14]

Answer:

s = √(3V/[8 in])

Step-by-step explanation:

Where are "the following functions" that were mentioned in this problem statement? Please share them. Thanks.

The volume of a right square pyramid is V = (1/3)(area of base)(height). In more depth, V = (1/3)(s²)(h). We want to solve this for s.

Multiplying both sides by 3 to eliminate the fractional coefficient, we get:

3V = s²(h), and so s² = 3V/h.

Taking the square root of this, we get:

s = √(3V/h).

Now let's substitute the given numerical value for the height:

s = √(3V/[8 in]). We could also label this as a(V) as is done in the problem statement.

3 0

3 years ago

How do you solve 5+4(x+9)=-3

dlinn [17]

Final answer: x=-11
1. distribute 4(x+9)
5+4x+36=-3
2. combine like terms
4x + 41 = -3
3. subtract 41 from each side
4x = -44
4. divide 4 from each side
x=-11

6 0

3 years ago

Read 2 more answers

Find the third order maclaurin polynomial. Use it to estimate the value of sqrt1.3

vodka [1.7K]

$\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}$ is the maclaurin polynomial and estimate value of $\sqrt{1.3}$ is 1.14. This can be obtained by using the formula to find the maclaurin polynomial.

<h3>Find the third order maclaurin polynomial:</h3>

Given the polynomial,

$f(x)=\sqrt{1+3x}=(1+3x)^{\frac{1}{2} }$

The formula to find the maclaurin polynomial,

$f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}$

Next we have to find f'(x), f''(x) and f'''(x),

$f'(x) = \frac{3}{2}(1+3x)^{-\frac{1}{2} }$

$f''(x) =-\frac{9}{4}(1+3x)^{-\frac{3}{2} }$

$f'''(x) = \frac{81}{8}(1+3x)^{-\frac{5}{2} }$

By putting x = 0 , we get,

$f(0)=(1+3(0))^{\frac{1}{2} }=1$

$f'(0) = \frac{3}{2}(1+3(0))^{-\frac{1}{2} }=\frac{3}{2}$

$f''(0) =-\frac{9}{4}(1+3(0))^{-\frac{3}{2} }=-\frac{9}{4}$

$f'''(0) = \frac{81}{8}(1+3(0))^{-\frac{5}{2} }=\frac{81}{8}$

Therefore the maclaurin polynomial by using the formula will be,

$\sqrt{1+3x}=f(0)+\frac{f'(0)}{1!}x+\frac{f''(0)}{2!}x^{2} + \frac{f'''(0)}{3!}x^{3}$

$\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}$

To find the value of $\sqrt{1.3}$ we can use the maclaurin polynomial,

$\sqrt{1.3}$ is $\sqrt{1+3x}$ with x = 1/10,

$\sqrt{1+3(1/10)}=1+\frac{3}{2} (1/10)-\frac{9}{8} (1/10)^{2} + \frac{81}{8}(1/10)^{3}$

$\sqrt{1+3(1/10)}=\frac{18247}{16000} = 1.14$

Hence $\sqrt{1+3x}=1+\frac{3}{2} x-\frac{9}{8} x^{2} + \frac{81}{8}x^{3}$ is the maclaurin polynomial and estimate value of $\sqrt{1.3}$ is 1.14.

Learn more about maclaurin polynomial here:

brainly.com/question/24188694

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6 0

1 year ago

Read 2 more answers

Ten slips of paper labeled from 1 to 5 are placed in a hat. The first slip of paper is not replaced before selecting the second

vagabundo [1.1K]

Answer:

1/10

Step-by-step explanation:

There are two numbers less than 3 (1 and 2), and one number greater than 4 (5).

When the first slip is drawn, there are five slips in the hat, so the probability of a number less than 3 is 2/5.

When the second slip is drawn, there are four slips in the hat, so the probability of a number greater than 4 is 1/4.

Therefore, the total probability is (2/5) (1/4) = 1/10

6 0

3 years ago

A chord is 10cm from the centre of a circle of radius 15cm. Find the length of the chord.

almond37 [142]

Answer: 21.44 cm

Step-by-step explanation:

Given

Radius r=15 cm

distance of chord from the center is 10 cm

From the figure, the length of the chord is AC

Applying Pythagoras

$\Rightarrow AO^2=OB^2+AB^2\\\Rightarrow AB^2=15^2-10^2\\\Rightarrow AB^2=225-100=115\\\Rightarrow AB=\sqrt{115}=10.72\ cm$

The length of the chord is $AC=2AB=21.44\ cm$

5 0

3 years ago