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Stella [2.4K]
3 years ago
6

Large helium–filled balloons are used to lift scientific equipment to high altitudes. What is the pressure inside such a balloon

if it starts out at sea level with a temperature of 9.0°C and rises to an altitude where its volume is fifteen times the original volume and its temperature is -40.0°C.What is the gauge pressure in atm)
Physics
1 answer:
rodikova [14]3 years ago
7 0

Answer:

-0.94492 atm

Explanation:

P_1 = Initial pressure = 1 atm

V_1 = Initial volume

T_1 = Inital temperature = 9°C

P_2 = Final pressure

V_2 = Final volume = 15V_1

T_1 = Final temperature = -40°C

We have the relation

\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow P_2=\dfrac{P_1V_1T_2}{T_1V_2}\\\Rightarrow P_2=\dfrac{1\times V_1\times (273.15-40)}{(273.15+9)\times 15V_1}\\\Rightarrow P_2=0.05508\ atm

Gauge pressure is given by

P_g=P_2-P_a\\\Rightarrow P_g=0.05508-1\\\Rightarrow P_g=-0.94492\ atm

The gauge pressure is -0.94492 atm

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Answer:

2 minutes or 120 seconds

Explanation:

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3 0
3 years ago
A ball is shot straight up from the surface of the
koban [17]
A ) The displacement:
d = v o t - (gt²) / 2 = 
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b ) v = v o - g t
0 = 19.6 m/s - 9.8 t    ( when the ball is at the highest point )
9.8 t = 19.6
t = 19.6 : 9.8
t = 2 s
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h = 19.6 m
c ) h = gt² / 2
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3 0
3 years ago
What is the number N0 of 99mTc atoms that must be present to have an activity of 15mCi?
svetoff [14.1K]
Base on my research, within 2 hours you have a number of atoms which remain. 
N= N0*2^(-t/6.020 = N= N0*2^-0.33223= 07943 N0

So, the number of atoms that are being disintegrated is N0-N=N0*(1-0.79430)=0.2057 N0

It must be equal to 15 mCi = 15*3.7*10^7= 5.55*10^8 atoms 

N0= 5.55*10*8/0.2057  = 2.698*10^9 atoms

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A 70.0 kg base runner moving at a speed of 4.0 m/s begins his slide into second base. The coefficient of friction between his cl
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B. 560 J

J. 1.2 m

Explanation:

v = Final velocity = 0

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\mu = Coefficient of friction = 0.7

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g = Acceleration due to gravity = 9.81\ \text{m/s}^2

Kinetic energy is given by

K=\dfrac{1}{2}m(v^2-u^2)\\\Rightarrow K=\dfrac{1}{2}\times 70\times (0^2-4^2)\\\Rightarrow K=-560\ \text{J}

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Acceleration is given by

a=-\mu g\\\Rightarrow a=-0.7\times 9.81\\\Rightarrow a=-6.867\ \text{m/s}^2

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4 0
3 years ago
A fire engine must lift 30 kg of water a vertical distance of 20 m each second. What is the amount of power needed for the water
ivolga24 [154]
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P = W / t
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Therefore,

P = mgd / t
P = (30)(9.81)(20) / 1 = 5886 W</span>
3 0
3 years ago
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