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3 years ago

How much time would it take to exert 700W of power while doing 700J of work?

Physics

1 answer:

Valentin [98]3 years ago

6 0

Answer:

The answer to your question is time = 1 s

Explanation:

Data

time = ?

Power = 700 W

Work = 700 J

Power is defined as the work done per unit of time.

Formula

Power = Work / Time

-Solve for time

Time = Work/Power

-Substitution

Time = 700 / 700

-Result

Time = 1 s

Conclusion

In 1 second and with 700 J there will be produced 700 watts

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3 years ago

Water flows steadily through a pipe of length L and radius R=75mm. The velocity distribution across the outlet is given by u=uma

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3 years ago

Imagine that asteroid A that has an escape velocity of 50 m/s. If asteroid B has twice the mass and twice the radius, it would h

padilas [110]

Answer:

The same as the escape velocity of asteorid A (50m/s)

Explanation:

The escape velocity is described as follows:

$v=\sqrt{\frac{2GM}{R}}$

where $G$ is the universal gravitational constant, $M$ is the mass of the asteroid and $R$ is the radius

and since the scape velocity is 50m/s:

$50m/s=\sqrt{\frac{2GM}{R}}$

Now, if the astroid B has twice mass and twice the radius, we have that tha mass is: $2M$

and the radius is: $2R$

inserting these values into the formula for escape velocity:

$v=\sqrt{\frac{2G(2M)}{2R} } =\sqrt{\frac{4GM}{2R} } =\sqrt{\frac{2GM}{R} }$

and we have found that $50m/s=\sqrt{\frac{2GM}{R}}$ , so the two asteroids have the same escape velocity.

We found that the expression for escape velocity remains the same as for asteroid A, this because both quantities (radius and mass) doubled, so it does not affect the equation.

The answer is

Asteroid B would have an escape velocity the same as the escape velocity of asteroid A

7 0

4 years ago

The magnitude of displacements a and b are 3m and 4m, respectively, c=a+b. What is the magnitude of c if the angel between a and

AysviL [449]

Answer:

(a) 7 m

(b) 1 m

Explanation:

Given:

The magnitude of displacement vector 'a' is 3 m

The magnitude of displacement vector 'b' is 4 m.

The vector 'c' is the vector sum of vectors 'a' and 'b'.

(a)

Now, when the angle between the vectors is 0°, it means that the vectors are in the same direction. When vectors are in the same direction, then their resultant magnitude is simply the sum of their magnitudes.

So, magnitude of 'c' when 'a' and 'b' are in same direction is given as:

$|\overrightarrow c|=|\overrightarrow a|+|\overrightarrow b|\\\\|\overrightarrow c|=3 + 4 = 7\ m$

Therefore, the magnitude of vector 'c' is 7 m when angle between 'a' and 'b' is 0°.

(b)

When the angle between the vectors is 180°, it means that the vectors are exactly in the opposite direction. When the vectors are in opposite direction, then their resultant magnitude is the subtraction of their magnitudes.

So, magnitude of 'c' when 'a' and 'b' are in opposite direction is:

$|\overrightarrow c|=||\overrightarrow a|-|\overrightarrow b||\\\\|\overrightarrow c|=|3 - 4| = 1\ m$

Therefore, the magnitude of vector 'c' is 1 m when angle between 'a' and 'b' is 180°.

4 0

3 years ago

(will give brainliest to whoever is first and gives reason) A mass is spun in a circle with a frequency of 40Hz. What is the per

Blizzard [7]

Answer:

$\huge\boxed{T = 0.025\ seconds}$

Explanation:

<u>Given:</u>

Frequency = f = 40 Hz

<u>Required:</u>

Time period = T = ?

<u>Formula:</u>

$\sf T = 1 / f$

<u>Solution:</u>

T = 1 / 40

T = 0.025 seconds

$\rule[225]{225}{2}$

Hope this helped!

4 0

3 years ago

How much time would it take to exert 700W of power while doing 700J of work?​

How much time would it take to exert 700W of power while doing 700J of work?