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3 years ago

HELPPPPPPPP PLEASWEW

Physics

1 answer:

zepelin [54]3 years ago

8 0

Answer:

For every increase in mass, the gravitational force increases.

If the total mass increases by a factor of 4, the gravitational force increases by a a factor of 4.

Explanation:

Compare the first row and the second row. Notice that m₂ stays the same, and m₁ triples. Notice that Fg also triples. So Fg is directly proportional to m₁.

Now compare the second row to the fourth row. Notice that m₁ stays the same and m₂ quadruples. Notice that Fg also quadruples. So Fg is also directly proportional to m₂.

Therefore:

Fg = k m₁ m₂

where k is a constant (in this case, k = 1).

So if the product m₁ m₂ increases by a factor of 4, then Fg will also increase by a factor of 4.

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3 years ago

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emmasim [6.3K]

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4 years ago

How do I do this physics problem about potential energy and kinetic energy?

larisa86 [58]

Ok i apologise for the messy working but I'll try and explain my attempt at logic

Also note i ignore any air resistance for this.

First i wrote the two equations I'd most likely need for this situation, the kinetic energy equation and the potential energy equation.

Because the energy right at the top of the swing motion is equal to the energy right in the "bottom" of the swing's motion (due to conservation of energy), i made the kinetic energy equal to the potential energy as indicated by Ek = Ep.

I also noted the "initial" and "final" height of the swing with hi and hf respectively.

So initially looking at this i thought, what the heck, there's no mass. Then i figured that using the conservation of energy law i could take the mass value from the Ek equation and use it in the Ep equation. So what i did was take the Ek equation and rearranged it for m as you can hopefully see. Then i substituted the rearranged Ek equation into the Ep equation.

So then the equation reads something like Ep = (rearranged Ek equation for m) × g (which is -9.81) × change in height (hf - hi).

Then i simplify the equation a little. When i multiply both sides by v^2 i can clearly see that there is one E on each side (at that stage i don't need to clarify which type of energy it is because Ek = Ep so they're just the same anyway). So i just canceled them out and square rooted both sides.

The answer i got was that the max velocity would be 4.85m/s 3sf, assuming no losses (eg energy lost to friction).

I do hope I'm right and i suppose it's better than a blank piece of paper good luck my dude xx

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3 years ago

A conducting bar moves along a circuit with a constant velocity. A constant magnetic field is perpendicular to the bar and circu

lana [24]

Answer:

0.500 T

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3 years ago