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sergiy2304 [10]
3 years ago
15

Which alignment aligns text to the left and right side margins?

Computers and Technology
1 answer:
FrozenT [24]3 years ago
5 0

Answer:

I have the same question but a little different I’m sorry that this is useless to you question but it’s not letting me ask my question. Sorry again-

Explanation:

What is a software system designed to locate information on the World Wide Web? Search browser Search engine Search keyword Search results

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WHICH PROGRAMMING LANGUAGES ARE THE BEST FOR PROGRAMMING?
Andrews [41]

Answer:

python is probably the best is you are a begginer

java and C++ are good too

6 0
3 years ago
Which of the following is NOT true about a flow chart?
SCORPION-xisa [38]
I think the answer is A
4 0
3 years ago
In python:
egoroff_w [7]

Python can be used to implement central of tendencies such as mean, median and mode using the statistic module

The program in Python, where comments are used to explain each line is as follows:

#This imports the statistics module

import statistics

#This defines the function that calculates the mode

def calcMode(myList):

   #This prints the mode

   print(statistics.multimode(myList))

#This defines the function that calculates the median

def calcMedian(myList):

   #This prints the median

   print(statistics.median(myList))

#The main method begins here

#This initializes the list

myList = []

#The following iteration gets input for the list

for i in range(10):

   myList.append(int(input()))

#This calls the calcMode method

calcMode(myList)

#This calls the calcMedian method

calcMedian(myList)

Read more about similar programs at:

brainly.com/question/25026386

8 0
3 years ago
Write c++ program to find maximum number for three variables using statement ?​
pantera1 [17]

Answer:

#include<iostream>

using namespace std;

int main(){

int n1, n2, n3;

cout<<"Enter any three numbers: ";

cin>>n1>>n2>>n3;

if(n1>=n2 && n1>=n3){

cout<<n1<<" is the maximum";}

else if(n2>=n1 && n2>=n3){

cout<<n2<<" is the maximum";}

else{

cout<<n3<<" is the maximum";}

return 0;

}

Explanation:

The program is written in C++ and to write this program, I assumed the three variables are integers. You can change from integer to double or float, if you wish.

This line declares n1, n2 and n3 as integers

int n1, n2, n3;

This line prompts user for three numbers

cout<<"Enter any three numbers: ";

This line gets user input for the three numbers

cin>>n1>>n2>>n3;

This if condition checks if n1 is the maximum and prints n1 as the maximum, if true

<em>if(n1>=n2 && n1>=n3){</em>

<em>cout<<n1<<" is the maximum";}</em>

This else if condition checks if n2 is the maximum and prints n2 as the maximum, if true

<em>else if(n2>=n1 && n2>=n3){</em>

<em>cout<<n2<<" is the maximum";}</em>

If the above conditions are false, then n3 is the maximum and this condition prints n3 as the maximum

<em>else{</em>

<em>cout<<n3<<" is the maximum";}</em>

return 0;

3 0
3 years ago
Write a program with a method that plays the guess a number game. The program should allow the user to pick a number between 1 a
nlexa [21]

Answer:

Please check the explanation

Explanation:

That's the code and it is done with the program in c++ according to instructions given in the question using binary search. It can guess the correct number in 10 or fewer attempts and also shows the number of attempts it took to guess the number.

​ #include <iostream> using namespace std; int guess() { string input; int l = 1, h = 1000; int mid = (l + h) / 2, count = 0; while (1) { //count the number of attemts to guess the number ++count; //cout << count << "\n"; cout << "\n"; cout << "Is " << mid << " correct? (y/n): "; cin >> input; //if input is y print the guessed no. and return if (input == "y") { cout << mid << " guessed in " << count << " attempts!\n"; return 1; } //if input is n ask the user if it's higher or lower than current guess if (input == "n") { cout << "Is the number greater than or less than the number ? (h/l): "; cin >> input; } //if input is higher assign mid incremented by 1 to low //else decrement mid by 1 and assign to high if (input == "h") l = mid + 1; else h = mid - 1; //calculate mid again according to input by user again mid = (l + h) / 2; } } int main() { cout << "****WELCOME TO THE GUESS THE NUMBER GAME!****\n"; cout << "Guess any number between 1 to 1000.\n"; cout << "This game depends on user giving correct answers and not changing their number middle of game.\n"; guess(); } ​

8 0
3 years ago
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