1 gal of water, seems pretty obvious, but it you want an equation where x = amt of water
:
x = .5(x+1)
x = .5x + .5
x - .5x = .5
.5x = .5
x = 1 gal
thanx
heyaaaaa
(1,47) (2,94) (3,141)
HOPE IT HELPS
Answer:
A) x = y+25
B) 35 minutes
C) 35 ≠85
Step-by-step explanation:
A)
As we know
X = number of minutes Eric plays basketball
Y = Number of minutes he plays volleyball
x+y= 95
x = y+25
B)
We will replace
x=y+25 in the first equation and we will get (y+25) + y =95
On solving,
y+25+y =95
25+2y=95
2y=95-25
2y=70
y = 70/2
y = 35 minutes
C) X = 35
x+y= 95
35+y =95
y= 95-35
y = 60 minutes
Substituting value of Y as 60 , we get
x = y+25
35 = 60+25
35 ≠85
Answer:
He can go 10.78 miles
Step-by-step explanation:
This problem can be solve by creating a proportion, knowing that 15.4 miles is to one gallon the same as "x" miles (our unknown) is to 0.7 gallons. This can be set in math terms as the equation that relates these two ratios of miles per gallon:
![\frac{15.4\,miles}{1\,gallon} =\frac{x }{0.7\,gallon}](https://tex.z-dn.net/?f=%5Cfrac%7B15.4%5C%2Cmiles%7D%7B1%5C%2Cgallon%7D%20%3D%5Cfrac%7Bx%20%7D%7B0.7%5C%2Cgallon%7D)
and to solve for the unknown number of mile, we multiply both sides of the equation by "0.7 gallon" in order to isolate our unknown:
![\frac{15.4\,miles}{1\,gallon} =\frac{x}{0.7\,gallon}\\\frac{15.4\,miles\,*\,0.7\,gallon}{1\,gallon} =x \\x=10.78\,miles](https://tex.z-dn.net/?f=%5Cfrac%7B15.4%5C%2Cmiles%7D%7B1%5C%2Cgallon%7D%20%3D%5Cfrac%7Bx%7D%7B0.7%5C%2Cgallon%7D%5C%5C%5Cfrac%7B15.4%5C%2Cmiles%5C%2C%2A%5C%2C0.7%5C%2Cgallon%7D%7B1%5C%2Cgallon%7D%20%3Dx%20%5C%5Cx%3D10.78%5C%2Cmiles)