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AleksandrR [38]
3 years ago
5

Suppose f(x,y,z) = x2 + y2 + z2 and W is the solid cylinder with height 7 and base radius 2 that is centered about the z-axis wi

th its base at z = −2. Enter θ as theta.
A) As an iterated integral, ∭WfdV = ∫BA∫DC∫FE dzdrdθ with limits of integration.

B) Evaluate the integral.
Mathematics
1 answer:
kipiarov [429]3 years ago
8 0

In cylindrical coordinates, <em>W</em> is the set of points

<em>W</em> = {(<em>r</em>, <em>θ</em>, <em>z</em>) : 0 ≤ <em>r</em> ≤ 2 and 0 ≤ <em>θ</em> ≤ 2<em>π</em> and -2 ≤ <em>z</em> ≤ 5}

(A) Then the integral of <em>f(x, y, z)</em> over <em>W</em> is

\displaystyle\iiint_W(x^2+y^2+z^2)\,\mathrm dV = \int_0^{2\pi}\int_0^2\int_{-2}^5r(r^2+z^2)\,\mathrm dz\,\mathrm dr\,\mathrm d\theta

(B)

\displaystyle \int_0^{2\pi}\int_0^2\int_{-2}^5r(r^2+z^2)\,\mathrm dz\,\mathrm dr\,\mathrm d\theta = 2\pi \int_0^2\int_{-2}^5(r^3+rz^2)\,\mathrm dz\,\mathrm dr \\\\\\= 2\pi \int_0^2\left(zr^3+\frac13rz^3\right)\bigg|_{z=-2}^{z=5}\,\mathrm dr \\\\\\= 2\pi \int_0^2\left(\frac{133}3r+7r^3\right)\,\mathrm dr \\\\\\= 2\pi \left(\frac{133}6r^2+\frac74r^4\right)\bigg|_{r=0}^{r=2} \\\\\\= 2\pi \left(\frac{110}3\right) = \boxed{\frac{220\pi}3}

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