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Soloha48 [4]
4 years ago
15

Which group allows you to add notes to your presentation?Ella has finished drafting her presentation. What should she do next?

Computers and Technology
2 answers:
Yanka [14]4 years ago
7 0

Definitely the last one...

liq [111]4 years ago
6 0
Ella should view the presentation as a slideshow to see how it will look to her audience. 
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Every file on a storage device has a _______. (a.) name (b.) size (c.)both of the above (d.) none of the above
zmey [24]
The correct answer is: C: both of the above, i. e. name and size.
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Orphaned data is also created by the way that the hard drive allocates space on the hard drive for information that the user wan
Anika [276]
It think the answer to that question maybe true
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Define an iterative function named append_ordered; it is passed two arguments: a linked list (ll) whose values are ordered from
enot [183]

Answer:

A python programming language (code) was used for this exercise.

The code is shown below in the explanation section

Explanation:

Solution

Python code:

class LN:

def __init__(self,value,next=None):

self.value = value

self.next = next

  def list_to_ll(self,l):

if l == []:

return None

front = rear = LN(l[0])

for v in l[1:]:

rear.next = LN(v)

rear = rear.next

return front

  def str_ll(self,ll):

answer = ''

while ll != None:

answer += str(ll.value)+'->'

ll = ll.next

return answer + 'None'

def append_ordered(self,ll,v):

ln1=LN(v); #create a node with the new value by creating an instance of the LN class

if ll is None: #if the linked list is empty

ll=ln1 #return the new created node

elif(ll.value >= ln1.value): #if the value to be add is smallest, append the linked list to it

ln1.next=ll

ll=ln1

else:

current=ll; #crate a temporary pointer to iterate over linked list

#iterate till the next node value is smaller than the new value and list is not over

while (current.next is not None and current.next.value < ln1.value):

current=current.next

ln1.next=current.next #save the current node in the next of the new node

current.next=ln1 #save new node in the next of current node

return ll

ln=LN(0); #create an instance of class LN

ll1=ln.list_to_ll([1,2,4,5]); #create a linked list of the list

answer=ln.str_ll(ll1);    

print(answer); #print the linked list

ll2=ln.append_ordered(ll1,3); #append the value 3 in the linked list

answer=ln.str_ll(ll2)

print(answer); #print the new linked list

Now,

  • If Linked list is empty then make the node as head and return it.
  • If value of the node to be inserted is smaller than value of head node, then insert the node at start and make it head.
  • In a loop, find the appropriate node after which the input node ( 10 ) is to be inserted.To find the appropriate node start from head,keep moving until you reach a node GN (12 ) who's value is greater than the input node. The node just before GN is the appropriate node (8).
  • Insert the node (10) after the appropriate node (8) found in step 3.

Note: Kindly find the output python code attached to the question below.

3 0
3 years ago
NEED HELP
amid [387]

Answer:

i would do B

Explanation:

I YOUNGI

I MIDDLE I

I   AGED  I

I     MEH   I

I_______ I

\ kinda old/

  \ ____ /

   I OLD I

3 0
3 years ago
Which of these statements regarding​ time-cost tradeoffs in CPM networks is​ true?
g100num [7]

Answer:

B. Crashing  is not possible unless there are multiple critical tasks.

8 0
3 years ago
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