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hammer [34]
3 years ago
12

Which one of these tasks best describes the process of localization?

Computers and Technology
1 answer:
Yanka [14]3 years ago
4 0
B like in mw2 they changed some of the versions because the airport mission was offensive to some 
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Which is the shortest and simplest tax form? <br> 1040 long form <br> 1040EZ<br> 1040A<br> 140E
Kay [80]
The answer is 1040EZ. That is the shortest and simplest tax form. 
7 0
3 years ago
Read 2 more answers
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
When creating loyal customers you must develop all of the following except: a. Smooth relationships b.customer marketing c. Dedi
bixtya [17]

Answer: I think a

Explanation: sorry I’m in wrong, have a great day!! :D

7 0
3 years ago
Read 2 more answers
describe briefly one scenario where records stored in a computer frequently need to be searched. state why the searches may be c
Gnoma [55]
Because the string is invalid or your source is not attached to your search engine.
4 0
3 years ago
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Write a program that would determine the day number in a non-leap year. For example, in a non-leap year, the day number for Dec
SOVA2 [1]

Answer:

In Python:

months = ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"]

daymonths = [31,28,31,30,31,30,31,31,30,31,30,31]

day = int(input("Day: "))

month = input("Month: ")

ind = months.index(month)

   

numday = 0

for i in range(ind):

   numday+=daymonths[i]

numday+=day

print(numday)    

Explanation:

This initializes the months to a list

months = ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"]

This initializes the corresponding days of each month to a list

daymonths = [31,28,31,30,31,30,31,31,30,31,30,31]

This gets the day from the user

day = int(input("Day: "))

This gets the month from the user

month = input("Month: ")

This gets the index of the month entered by the user

ind = months.index(month)

This initializes the sum of days to 0

numday = 0

This adds up the days of the months before the month entered by the user

<em>for i in range(ind):</em>

<em>    numday+=daymonths[i]</em>

This adds the day number to the sum of the months

numday+=day

This prints  the required number of days

print(numday)    

<em>Note that: Error checking is not done in this program</em>

7 0
3 years ago
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