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Dovator [93]
4 years ago
9

Sally soccer team play 25 games in 117 of them. What percentage of the team win

Mathematics
1 answer:
suter [353]4 years ago
8 0

(Its 17 of them actually)

p=percent

17/25=p/100

So 25*4=100.

so that means that we need to multiply the numerator 17 by 4 also. 17*4=69.

So, they won 68% of their games.

Hope this helps :^)

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Which is the equation of the given line in slope-intercept form
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Answer: The Slope-Intercept Form equation is y=mx+b

i think the answer is y=3x+2 but i hope this helps

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Solve for y<br> a. 4x + 5y = 25
AfilCa [17]

Answer:

y = -4/5x + 5

Step-by-step explanation:

In order to solve for y, we need to isolate the variable. First, let's subtract 4x on each side. After doing said step, we should now have this equation:

5y = -4x + 25

Next, we need to divide 5 on each side, giving us this new equation:

y = -4/5x + 5

There you go! Let me know if I did anything wrong ^-^

5 0
3 years ago
Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>​
sladkih [1.3K]

Answer:

\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2

\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta

17)  Given:

  • \theta = 240°
  • r = 16 ft

\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2

19)  Given:

  • \theta=\dfrac{3 \pi}{2}
  • r = 14 cm

\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2

21)  Given:

  • \theta=\dfrac{ \pi}{2}
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\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2

23)  Given:

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\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2

3 0
2 years ago
At a local University, it is reported that 81% of students own a wireless device. If 5 students are selected at random, what is
Sphinxa [80]

Answer:

34.87% probability that all 5 have a wireless device

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

81% of students own a wireless device.

This means that p = 0.81

If 5 students are selected at random, what is the probability that all 5 have a wireless device?

This is P(X = 5) when n = 5. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.81)^{5}.(0.19)^{0} = 0.3487

34.87% probability that all 5 have a wireless device

5 0
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iren2701 [21]

Answer:

$183

Step-by-step explanation:

619 - (270 + 166) = x

x = 183

4 0
3 years ago
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