All categories

2 years ago

Find the missing dimension of the cone

Mathematics

1 answer:

larisa86 [58]2 years ago

6 0

Answer:

h=1ft

Step-by-step explanation:

The volume of a cone is:

v=πr^h/3

plug in the values (I am assuming not 1/18π but 1/18×π):

1/18π= π1/3^2h/3

Get rid of the radius:

1/3^2=1/9

Continue:

π/18= πh/3*1/9= πh/18

Remove the denominators:

π=πh

Divide both sides by π :

h=1

You might be interested in

I need help with this

Rzqust [24]

C is the answer to the question

7 0

3 years ago

I’m struggling with this question. can you please help me?

dem82 [27]

Answer:

50°

Step-by-step explanation:

∠ RST = (arc QC - arc RT) / 2

= (150° - 50°) / 2

= 50°

7 0

2 years ago

What is the answer for -2p > -16

OlgaM077 [116]

Answer:

p<8

Step-by-step explanation:

We multiply both sides by -1 to get

But remember, when you do that you reverse it, so we turn > into a <

2p<16

we divide both sides by 2

p<8

Hope this helps :)

5 0

2 years ago

Read 2 more answers

Somebody plz help me this is due tomorrow plzz!!!!

Eddi Din [679]

For number one if you add up the numbers in each square you’ll notice each square is the same sum. You can use a similar strategy for number two.

4 0

3 years ago

If anyone is tailented on maths they can solve it plzz help me with solution

Vitek1552 [10]

Answer:

Step-by-step explanation:

b). $(\frac{-7}{11})^{-8}\times [(\frac{-7}{11})^{-7}\div (\frac{-7}{11})^{-8}]^4$

= $(\frac{-7}{11})^{-8}\times [(\frac{-7}{11})^{-7}\times (\frac{-7}{11})^{8}]^4$ [Since, $\frac{1}{a^{-1}}=a$ ]

= $(\frac{-7}{11})^{-8}\times [(\frac{-7}{11})^{8-7}]^4$

= $(\frac{-7}{11})^{-8+4}$

= $(\frac{-7}{11})^{-4}$

= $(-\frac{11}{7})^4$

= $\frac{14641}{2401}$

c). $(5^{-1}-10^{-1})^{-1}+(3^{-1}-5^{-1})^{-1}$

= $(\frac{1}{5}-\frac{1}{10})^{-1}+(\frac{1}{3}-\frac{1}{5})^{-1}$

= $(\frac{2}{10}-\frac{1}{10})^{-1}+(\frac{5}{15}-\frac{3}{15})^{-1}$

= $(\frac{1}{10})^{-1}+(\frac{2}{15})^{-1}$

= 10 + $\frac{15}{2}$

= 10 + 7.5

= 17.5

3 0

2 years ago

Read 2 more answers