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timama [110]
3 years ago
11

What materials can I find at home and make a cell phone tower​

Computers and Technology
1 answer:
MAVERICK [17]3 years ago
4 0

Answer:

you cant

Explanation:

You simply cant make a tower from materials found in a household

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Write a program with the total change amount as an integer input, and output the change using the fewest coins, one coin type pe
riadik2000 [5.3K]

Answer:

In Python:

cents = int(input("Cents: "))

dollars = int(cents/100)

quarters = int((cents - 100*dollars)/25)

dimes = int((cents - 100*dollars- 25*quarters)/10)

nickels = int((cents - 100*dollars- 25*quarters-10*dimes)/5)

pennies = cents - 100*dollars- 25*quarters-10*dimes-5*nickels

if not(dollars == 0):

   if dollars > 1:

       print(str(dollars)+" dollars")

   else:

       print(str(dollars)+" dollar")

if not(quarters == 0):

   if quarters > 1:

       print(str(quarters)+" quarters")

   else:

       print(str(quarters)+" quarter")

if not(dimes == 0):

   if dimes > 1:

       print(str(dimes)+" dimes")

   else:

       print(str(dimes)+" dime")

if not(nickels == 0):

   if nickels > 1:

       print(str(nickels)+" nickels")

   else:

       print(str(nickels)+" nickel")

if not(pennies == 0):

   if pennies > 1:

       print(str(pennies)+" pennies")

   else:

       print(str(pennies)+" penny")

   

Explanation:

A prompt to input amount in cents

cents = int(input("Cents: "))

Convert cents to dollars

dollars = int(cents/100)

Convert the remaining cents to quarters

quarters = int((cents - 100*dollars)/25)

Convert the remaining cents to dimes

dimes = int((cents - 100*dollars- 25*quarters)/10)

Convert the remaining cents to nickels

nickels = int((cents - 100*dollars- 25*quarters-10*dimes)/5)

Convert the remaining cents to pennies

pennies = cents - 100*dollars- 25*quarters-10*dimes-5*nickels

This checks if dollars is not 0

<em>if not(dollars == 0):</em>

If greater than 1, it prints dollars (plural)

<em>    if dollars > 1:</em>

<em>        print(str(dollars)+" dollars")</em>

Otherwise, prints dollar (singular)

<em>    else:</em>

<em>        print(str(dollars)+" dollar")</em>

This checks if quarters is not 0

<em>if not(quarters == 0):</em>

If greater than 1, it prints quarters (plural)

<em>    if quarters > 1:</em>

<em>        print(str(quarters)+" quarters")</em>

Otherwise, prints quarter (singular)

<em>    else:</em>

<em>        print(str(quarters)+" quarter")</em>

This checks if dimes is not 0

<em>if not(dimes == 0):</em>

If greater than 1, it prints dimes (plural)

<em>    if dimes > 1:</em>

<em>        print(str(dimes)+" dimes")</em>

Otherwise, prints dime (singular)

<em>    else:</em>

<em>        print(str(dimes)+" dime")</em>

This checks if nickels is not 0

<em>if not(nickels == 0):</em>

If greater than 1, it prints nickels (plural)

<em>    if nickels > 1:</em>

<em>        print(str(nickels)+" nickels")</em>

Otherwise, prints nickel (singular)

<em>    else:</em>

<em>        print(str(nickels)+" nickel")</em>

This checks if pennies is not 0

<em>if not(pennies == 0):</em>

If greater than 1, it prints pennies (plural)

<em>    if pennies > 1:</em>

<em>        print(str(pennies)+" pennies")</em>

Otherwise, prints penny (singular)

<em>    else:</em>

<em>        print(str(pennies)+" penny")</em>

<em>    </em>

4 0
3 years ago
Why is page formatting important??​
Lorico [155]

Answer:

Perhaps one of the most important things you can learn in Microsoft Word is how to format your page with elements such as margins and page breaks. Formatting your pages makes them look more attractive and makes them easier to read.

7 0
3 years ago
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3) An algorithm has a run time of O(nk ) for some integer k. On an input of size 500, the algorithm takes 16 seconds to run. On
lukranit [14]

Answer:

The value of k is 4

Explanation:

Solution

Given that:

k = integer

Input size = 500

The algorithm takes a run of = 16 seconds

Input size = 750

The algorithm takes a run of = 81 seconds

Now,

We have to determine the value of k

The equation is shown below:

(500)^k /16 = (750) ^k /81

Thus

(750/500)^ k = 81/16

= (3/2)^k

=(3/2)^ 4

k is = 4

6 0
3 years ago
What is the answer to this A term career is usually applied to a Someone please HEEEEEEEEEELP MEEEEEEE. THX
spin [16.1K]

Answer:

Position that allows for professional growth and advancement

The term career is used in a number of ways but is usually applied to means the same thing: a position that allows for professional growth and advancement. It relates to a person’s occupation or profession and his journey of life, learning (training or formal education)  and work.  

4 0
3 years ago
_____ refers to the busiest calling hour of the day, week, month or year. And _____ refers to the average length of time the sub
Butoxors [25]

Answer: a) busy hour  b) Average handle time.

Explanation:

a) In order to design a telephony circuit, trunk, or call center, it is needed to take into account the busiest calling hour (as a "sliding" 60-minute period) in one day, or week, month or year, generally calculated as an average.

This period is called the "busy hour" and is used to compute the traffic intensity, in Erlangs, considering that if the circuit is busy 100% of the time during 3600 seconds, it will be cursing 1 Erl of traffic.

This traffic can result from 60 calls of 1 min each, 36 calls of 100 sec each, or any combination that have the same outcome of 1 Erl.

b) In order to define, for instance, the number of employees in a call center, a very important parameter is the average time used for each call, adding the queuing time, the true talk time and any other time needed to  set up a successful call, i.e., the time that the subscriber stays on the phone after putting the call.

This time is known as AHT (Average Handle Time).

3 0
4 years ago
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