What two skills are most important for a meteorologist
2 answers:
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Answer:
The answer is "Variable min is defined in the "FindMin()" method, but is used in the main method".
Explanation:
Following are the correct code to the given question:
#include <iostream>//header file
using namespace std;
int FindMin(int a, int b) //defining a method FindMin that takes two integer parameters
{
int min; //defining integer variable
if (a < b) //use if to check a value less than b
{
min = a; //holding smallest value in min
}
else //defining else block
{
min = b;//holding smallest value in min
}
return min; //return min value
}
int main() //defining main method
{
int x,y,min; //defining integer variable
cin >> x; //input value
cin >> y; //input value
min = FindMin(x,y); //holding method return value in min variable
cout<<"The smaller number is: "<<min<< endl; //print method value with message
return 0;
}
Output:
Please find the attached file.
In the code, a method "FindMin" is defined that takes two integer parameters "a,b" and inside the method, an integer variable "min" is declared that uses a conditional statement that checks the smallest value that store in the min variable and return its value.
In the main method, three integer variable is declared in which two is used for hold value from user-end pass into the method and store its return value in min variable and print value with the message.
