Hey guys what is 10+12-34+68-4778855+5676+77-6865666+3456-7658×45×23+35566÷79997 = ?
2 answers:
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Answer:
.
Step-by-step explanation:
We need to find the factors of given equation;
Solution:
On Solving the above equation we get;
Now First we will take common factor from first 2 terms which is we get;
Now we will take the common factor from the last 2 terms which is 3 we get;
Here we get 2 terms in which is common factor.
Hence After factorizing the given equation we get .
<h3>(-3j²k³)²(2j²k)³</h3>
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!