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vladimir1956 [14]
2 years ago
9

Which expression is equivalent to? Please help me quick!

Mathematics
1 answer:
sweet-ann [11.9K]2 years ago
8 0

Hi!

The answer to this expression is x^4 or d

Feel free to give brainliest!

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You roll a standard, six-sided number cube. What is the probability of rolling a prime number or a number greater than 3?
Debora [2.8K]
Answer:
B. 5/6

Answer explained:
Prime numbers include 2, 3, and 5 and all numbers after 3 are 4, 5, 6 so 5 out of 6 or 5/6
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Hai are yall real:/?
sammy [17]

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yes surprisingly

Step-by-step explanation:

4 0
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Can someone help me with this? thank you!
hammer [34]

Answer:

<u>240cm³</u>

Step-by-step explanation:

To find our answer we will <u>multiply</u> the <em>volume, width, and height</em>.

4 · 20 · 3 = 240.  Therefore, <u>240cm³ is our answer.</u>  

<em>Have a good day!</em>

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2 years ago
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Write (3a)^3 without exponents
makkiz [27]

Answer: 27a^3

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7 0
3 years ago
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Could you help me to solve the problem below the cost for producing x items is 50x+300 and the revenue for selling x items is 90
s344n2d4d5 [400]

Answer:

Profit function: P(x) = -0.5x^2 + 40x - 300

profit of $50: x = 10 and x = 70

NOT possible to make a profit of $2,500, because maximum profit is $500

Step-by-step explanation:

(Assuming the correct revenue function is 90x−0.5x^2)

The cost function is given by:

C(x) = 50x + 300

And the revenue function is given by:

R(x) = 90x - 0.5x^2

The profit function is given by the revenue minus the cost, so we have:

P(x) = R(x) - C(x)

P(x) = 90x - 0.5x^2 - 50x - 300

P(x) = -0.5x^2 + 40x - 300

To find the points where the profit is $50, we use P(x) = 50 and then find the values of x:

50 = -0.5x^2 + 40x - 300

-0.5x^2 + 40x - 350 = 0

x^2 - 80x + 700 = 0

Using Bhaskara's formula, we have:

\Delta = b^2 - 4ac = (-80)^2 - 4*700 = 3600

x_1 = (-b + \sqrt{\Delta})/2a = (80 + 60)/2 = 70

x_2 = (-b - \sqrt{\Delta})/2a = (80 - 60)/2 = 10

So the values of x that give a profit of $50 are x = 10 and x = 70

To find if it's possible to make a profit of $2,500, we need to find the maximum profit, that is, the maximum of the function P(x).

The maximum value of P(x) is in the vertex. The x-coordinate of the vertex is given by:

x_v = -b/2a = 80/2 = 40

Using this value of x, we can find the maximum profit:

P(40) = -0.5(40)^2 + 40*40 - 300 = $500

The maximum profit is $500, so it is NOT possible to make a profit of $2,500.

3 0
3 years ago
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