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dmitriy555 [2]
3 years ago
11

0.095-20/5= Write it as a decimal

Mathematics
2 answers:
Harrizon [31]3 years ago
8 0
-3.905 is the awnser
rodikova [14]3 years ago
4 0

Answer:

-3.905

Step-by-step explanation:

0.095 - 20/5

0.095 - 4

-|4-0.095|

-|3.905|

-3.905

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Simplify the following expression into simplest form with all positive exponents
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I'm am pretty sure that the answer is 320. Hope this helps!

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mr. bird leaves for a walk at 7:50 a.m. she allows 25 minutes later what time does she arrive to work​
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Answer: 8:15

Step-by-step explanation:

If she leaves at 7:50 and arrives to work 25 minutes later, then she will get there at 8:15.

Something easy you could use:

7:50 25

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its first year of operation Big Lake Camp had 40 campers this year the tents was under 80% of the first year how many campers pa
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6 0
3 years ago
A study of homeowners in the 5th congressional district in Maryland found that their annual household incomes are normally distr
tino4ka555 [31]

Answer:

The minimum income level for this target group is of $51,253.6.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of $41,182 and a standard deviation of $11,990

This means that \mu = 41182, \sigma = 11990

Find the minimum income level for this target group.

The 100 - 20 = 80th percentile, which is X when Z has a p-value of 0.8, so X when Z = 0.84.

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - 41182}{11990}

X - 41182 = 0.84*11990

X = 51253.6

The minimum income level for this target group is of $51,253.6.

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