Answer:
The last choice availablle
Step-by-step explanation:
The way you can tell the points the function has in common with the x-axis (also known as the solutions, roots, or zeros of the functiion) you have to factor it to solve for x. When you throw this into the quadratic formula you get that there is a negative under the square root sign, which is indicative of imaginary solutions. Imaginary solutions do NOT cross the x-axis. So the answer to your problem is the last choice.
X = 4
The first equation can be substituted into the second one. It would be: 2(-2x+5)=x-10 and after solving it, x = 4
Answer:-2.3
Step-by-step explanation:
The answer is B djiekljfjroeo
9514 1404 393
Answer:
D. (-3, -2)
Step-by-step explanation:
The equations have different coefficients for x and y, so will have one solution. The solutions offered are easily tested in either equation.
Using (x, y) = (-2, -3):
x = y -1 ⇒ -2 = -3 -1 . . . . False
Using (x, y) = (-3, -2):
x = y -1 ⇒ -3 = -2 -1 . . . .True
2x = 3y ⇒ 2(-3) = 3(-2) . . . . True
The solution is (-3, -2).
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If you'd like to solve the set of equations, substitution for x works nicely.
2(y -1) = 3y
2y -2 = 3y . . eliminate parentheses
-2 = y . . . . . . subtract 2y
x = -2 -1 = -3
The solution is (x, y) = (-3, -2).