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3 years ago

14

Skylar and Rodrigo each recorded how far they traveled while skateboarding. Skylar traveled 65 feet in 5 seconds and Rodrigo tra

veled 108 feet in 8 seconds. How much farther did Rodrigo travel per second than Skylar?
PLEASE PUT YOUR ANSWER IN FEET !

1 answer:

Elena-2011 [213]3 years ago

4 0

Skylar went 13ft per second
Rodrigo went 13 1/2 ft per second
So, 1/2 a ft per second

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PLEASE HELP!!!!

juin [17]

$\displaystyle \sum_{n=1}^{5} (-5 -4(n-1))$

$\displaystyle =\sum_{n=1}^{5} (-1-4n)$

Answer: the summation from n equals one to 5 of quantity negative 1 minus 4 times n

4 0

3 years ago

Please help fast‼️‼️

Aleks [24]

Hello from MrBillDoesMath!

Answer: factor = 4

Discussion:

Look at the sequence of numbers

1/64, 1/16, 1/4, 1, 4

It's seems clear that multiplying a term by 4 gives the next term in the sequence.

Thank you,

MrB

4 0

2 years ago

The sum of three consecutive even numbers is 66. What is the smallest of these numbers?

ahrayia [7]

Your answer would be 22 because it says <em>"sum"</em> which means <u>add.</u> Then it says "<em>of three consecutive <u>even</u> numbers</em>" which means you're going to be adding <u>three</u> of the <em>same <u>even</u> number </em>to get 66. 22 is an <u>even</u> number, so let's try it out: 22 + 22 + 22 = 66. (You can also divide 66 by 3.) 22 is the cOrrect answer.

Hope this helps,
♥<em>A.W.E.<u>S.W.A.N.</u></em>♥

8 0

3 years ago

Evaluate the expression 2x+6 if x = 4

JulijaS [17]

2(4)+6
8+6
=14
you’re welcome :)

8 0

3 years ago

A= [2, 3; 2, 1], B=[3; 5]. Find AB & BA if possible

oksano4ka [1.4K]

Answer:

The value of AB is $\left[\begin{array}{ccc}21\\11\end{array}\right]$ and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

$A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right]$ , $B=\left[\begin{array}{ccc}3\\5\end{array}\right]$

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2 and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

$AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]$

$AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]$

$AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]$

$AB=\left[\begin{array}{ccc}21\\11\end{array}\right]$

Hence, the value of AB is $\left[\begin{array}{ccc}21\\11\end{array}\right]$

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1 and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0

3 years ago