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meriva
3 years ago
7

How to solve 2x² - x - 3 = 0

Mathematics
1 answer:
Pie3 years ago
6 0
2x²- x -3 = 0 ⇒ 2x²-x= 0 + 3 ⇒ 2x² - x = 3 ⇒ 2x = 3 ⇒ x = 1.5
            
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If cos x=8/17, and 270° &lt; x &lt; 360°<br> what is cos(2x)?
svp [43]

Answer:  \bold{-\dfrac{161}{289}}

<u>Step-by-step explanation:</u>

Given: cos x = \dfrac{8}{17}, x is in Quadrant 4

Use Pythagorean Theorem to find sin x:

8² + y² = 17²    

      y² = 17² - 8²

      y² = 289 - 64

      y² = 225

      y = 15

→    sin x = -\dfrac{15}{17}

Use the double angle formula to find cos (2x):

cos (2x) = cos^2 x - sin^2 x\\\\.\qquad=\bigg(\dfrac{8}{17}\bigg)^2-\bigg(-\dfrac{15}{17}\bigg)^2\\\\\\.\qquad=\dfrac{64}{289}-\dfrac{225}{289}\\\\\\.\qquad=-\dfrac{161}{289}

             

8 0
3 years ago
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Think I know this one but could do with some help
Andrei [34K]
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7 0
2 years ago
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Anna11 [10]

Answer:

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3 0
2 years ago
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Step-by-step explanation:

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What is 25 1/2 divided by 6 1/4
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6 0
3 years ago
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