1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
meriva
3 years ago
7

How to solve 2x² - x - 3 = 0

Mathematics
1 answer:
Pie3 years ago
6 0
2x²- x -3 = 0 ⇒ 2x²-x= 0 + 3 ⇒ 2x² - x = 3 ⇒ 2x = 3 ⇒ x = 1.5
            
You might be interested in
Maggie missed 8 out of her last 20 free throws. What is the experimental probability that Maggie will miss her next free-throw a
prisoha [69]
%5 so ya it is five percent
4 0
3 years ago
Raymond works for an architecture firm. His company has a contract to design a building on a rectangular plot of land that has a
yKpoI14uk [10]

Answer:

1286 meters long

Step-by-step explanation:

421,808 divided by the width of the plot gives you 1,286 meters for the width.

5 0
3 years ago
Please help me no links
Sauron [17]
Its 81 good job on the question
8 0
3 years ago
Read 2 more answers
Jessica sells handbags for $50 each. If she makes $650, how many handbags did she sell?
satela [25.4K]

Answer:

13

Step-by-step explanation:

<em>Divide 50 from 650.</em>

<em>650 / 50 </em>

<em>13</em>

<em>This proves she sold 13 handbags</em>

6 0
3 years ago
You toss three 6-sided dice and record the sum of the three faces facing up. a) Describe precisely a sample space S for this exp
timama [110]

Answer:

a.)Sample space means all possible outcomes, since we know the dice are 6 face, then the sample space becomes all possible outcomes when we toss the die.

b.) 9/216

c.) 9/216

d.) 212/216

Step-by-step explanation:

Sample space means all possible outcomes, since we know the dice are 6 face, then the sample space becomes all possible outcomes when we toss the die.

[1,1,1] [1,1,2] [1,1,3] [1,1,4] [1,1,5] [1,1,6]

[1,2,1] [1,2,2] [1,2,3] [1,2,4] [1,2,5] [1,2,6],

[1,3,1] [1,3,2] [1,3,3] [1,3,4] [1,3,5] [1,3,6]

[1,4,1] [1,4,2] [1,4,3] [1,4,4] [1,4,5] [1,4,6]

[1,5,1] [1,5,2] [1,5,3] [1,5,4] [1,5,5] [1,5,6]

[1,6,1] [1,6,2] [1,6,3] [1,6,4] [1,6,5] [1,6,6]

[2,1,1] [2,1,2] [2,1,3] [2,1,4] [2,1,5] [2,1,6]

[2,2,1] [2,2,2] [2,2,3] [2,2,4] [2,2,5] [2,2,6],

[2,3,1] [2,3,2] [2,3,3] [2,3,4] [2,3,5] [2,3,6]

[2,4,1] [2,4,2] [2,4,3] [2,4,4] [2,4,5] [2,4,6]

[2,5,1] [2,5,2] [2,5,3] [2,5,4] [2,5,5] [2,5,6]

[2,6,1] [2,6,2] [2,6,3] [2,6,4] [2,6,5] [2,6,6]

[3,1,1] [3,1,2] [3,1,3] [3,1,4] [3,1,5] [3,1,6]

[3,2,1] [3,2,2] [3,2,3] [3,2,4] [3,2,5] [3,2,6],

[3,3,1] [3,3,2] [3,3,3] [3,3,4] [3,3,5] [3,3,6]

[3,4,1] [3,4,2] [3,4,3] [3,4,4] [3,4,5] [3,4,6]

[3,5,1] [3,5,2] [3,5,3] [3,5,4] [3,5,5] [3,5,6]

[3,6,1] [3,6,2] [3,6,3] [3,6,4] [3,6,5] [3,6,6]

[4,1,1] [4,1,2] [4,1,3] [4,1,4] [4,1,5] [4,1,6]

[4,2,1] [4,2,2] [4,2,3] [4,2,4] [4,2,5] [4,2,6],

[4,3,1] [4,3,2] [4,3,3] [4,3,4] [4,3,5] [4,3,6]

[4,4,1] [4,4,2] [4,4,3] [4,4,4] [4,4,5] [4,4,6]

[4,5,1] [4,5,2] [4,5,3] [4,5,4] [4,5,5] [4,5,6]

[4,6,1] [4,6,2] [4,6,3] [4,6,4] [4,6,5] [4,6,6]

[5,1,1] [5,1,2] [5,1,3] [5,1,4] [5,1,5] [5,1,6]

[5,2,1] [5,2,2] [5,2,3] [5,2,4] [5,2,5] [5,2,6],

[5,3,1] [5,3,2] [5,3,3] [5,3,4] [5,3,5] [5,3,6]

[5,4,1] [5,4,2] [5,4,3] [5,4,4] [5,4,5] [5,4,6]

[5,5,1] [5,5,2] [5,5,3] [5,5,4] [5,5,5] [5,5,6]

[5,6,1] [5,6,2] [5,6,3] [5,6,4] [5,6,5] [5,6,6]

[6,1,1] [6,1,2] [6,1,3] [6,1,4] [6,1,5] [6,1,6]

[6,2,1] [6,2,2] [6,2,3] [6,2,4] [6,2,5] [6,2,6],

[6,3,1] [6,3,2] [6,3,3] [6,3,4] [6,3,5] [6,3,6]

[6,4,1] [6,4,2] [6,4,3] [6,4,4] [6,4,5] [6,4,6]

[6,5,1] [6,5,2] [6,5,3] [6,5,4] [6,5,5] [6,5,6]

[6,6,1] [6,6,2] [6,6,3] [6,6,4] [6,6,5] [6,6,6]

b.) Probability that the sum is 16 or more is

Pr[4,6,6] + pr[5,5,6] + pr [ 5,6,5] + pr [5,6,6] + pr [6,5,5] + pr [6,5,6] + pr [6,6,4] + pr[6,6,5] + pr [6,6,6]

Becomes:

[1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ = 9/216

Probability that the sum is 4 or 5 is

Pr [ 1,1,2] or pr[1,2,2] or pr [1,1,3] or pr [1,2,1] or pr[2,1,2] or pr[1,3,1] or pr[3,1,1] or pr[2,1,1] or pr[2,2,1]

Becomes:

[1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ = 9/216

Probability that the sum is less than 17

We take it as:

1- probability that the sum is 17 and above.

Now probability that the sum is 17 and above becomes

pr[5,6,6] or pr[6,5,6] or pr[6,6,5] or pr[6,6,6]

= [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ = 4/216

Hence, probability that the sum is less than 17 becomes:

1-4/216 = 212/216.

3 0
3 years ago
Other questions:
  • Write the equation in standard form for the circle that has a diameter with endpoints (0,8) and (0, - 8)
    11·2 answers
  • 1. A physics contest has 30 multiple-choice
    6·1 answer
  • 0.2x + 0.5y = 4<br> -0.1x + 0.3y = -2
    6·2 answers
  • Solve: In2x + In 2= 0
    10·1 answer
  • A T-Rex made 16 waffles for his friends for breakfast. 5 were blueberry waffles and the rest were chocolate chip waffles. How ma
    11·2 answers
  • Anyone know the answer to this
    10·2 answers
  • Please answer, fifteen pts!<br><br> 8x -4 &lt; -36.<br><br> Please explain/show work!
    10·1 answer
  • During summer vacation, Erin read, on average, 4 pages per night. Once she returned to school, she averaged 3 pages per night. W
    10·1 answer
  • In an arithmetic progression, the sixth term is equal to 10.5; and the difference is 1.5. Find the first term and the sum of the
    6·1 answer
  • <img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B%200%7D%5E%20%7B%5Clarge%5Cfrac%7B%5Cpi%7D4%7D%20%20%20%5Csqrt%7B%20%5Cta
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!