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3 years ago

F(v)=6+v^2 how do I solve

Mathematics

1 answer:

Nostrana [21]3 years ago

6 0

Step-by-step explanation:

Well, this is a function. In order to solve this, you need a v value. Once you get a v value, you can plug into into 6+v^2 and wala- you get your answer.

Example, lets say

v is 3

then

F(3) = 6 + 3^2

f(3) = 6 + 9

f(3) =15

Hope this helped

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explain fractions and, explain if I don't get fractions what do I need to relearn to understand fractions, if you don't understa

Andru [333]

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3 years ago

5.69÷7 you can round to nearest hundredth

pogonyaev

The answer would be .81 becuase you can't round the 1 up to 2 becuase the number in the thousandths place is not above 5.
Hope this helps!!

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3 years ago

the ratio of the length to the width to the height of an open rectangular tank is 10:5:8. The height of the tank is 18 feet long

balandron [24]

Answer:

4556.25

Step-by-step explanation:

10:5:8=x:y:18

18/8=2.25

x=2.25x10=22.5

y=2.25x5=11.25

11.25x22.5x18=4556.25

8 0

2 years ago

Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

$\rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]$

5 0

3 years ago

9x² - 12x + 4 <br><br>pls need ans.

kolezko [41]

Step-by-step explanation:

$\tt{9 {x}^{2} - 12x + 4}$

Here, the second order of polynomial ax² + bx + c is factorized and expressed as the product of two linear factors. First, we have to find the two numbers that adds to 12 and if we multiply those numbers , we get 36 ( The two numbers should be 6 and 6 ).

⟶ $\tt{9 {x}^{2} - (6 + 6)x + 4}$