Answer is: amount of sugar in milk chocolade is 3333 mg.
To solve this question, make proportion: if 12,00 grams of milk chocolate contain 8,00 grams of sugar, than 5,00 grams contain:
12,000 g : 8,000 g = 5,000 g : m(sugar).
12,000 g · m(sugar) = 8,000 g · 5,000 g.
m(sugar) = 40,000 ÷ 12,000.
m(sugar) = 3,333 g = 3333 mg.
Answer:
Explanation:
The expression for Clausius-Clapeyron Equation is shown below as:
Where,
P is the vapor pressure
ΔHvap is the Enthalpy of Vaporization
R is the gas constant (8.314×10⁻³ kJ /mol K)
c is the constant.
For two situations and phases, the equation becomes:
Given:
= 13.95 torr
= 144.78 torr
= 25°C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (25 + 273.15) K = 298.15 K
= 298.15 K
= 75°C = 348.15 K
So,
2H2 + O2 ---> 2H2O
1 mole of H2 = 2g
1 mole of O2 = 32g
1 mole of H2O = 18g
according to the reaction:
2*2g H2---------------32g O2
1,6g H2----------------- x g O2
x = 12,8g O2
so reaction is stechiometric
32g O2---------------- 2*18g H2O
12,8g O2 -------------- x
x = 14,4g H2O
answer: 14,4g of water vapour
Molecule add molecule is a compound
Answer:
Explanation:
Hello!
In this case, since the net ionic equation of a chemical reaction shows up the ionic species that result from the simplification of the spectator ions, which are those at both reactants and products sides, we take into account that aqueous species ionize into ions whereas liquid, solid and gas species remain unionized. In such a way, for the reaction of cesium phosphate and silver nitrate we can write the complete molecular equation:
Whereas the three aqueous salts are ionized in order to write the following complete ionic equation:
In such a way, since the cesium and nitrate ions are the spectator ions because of the aforementioned, the net ionic equation turns out:
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