Side = 8m
He increases length by 2m and reduces width by 2m
(a.) New dimensions will be -
Length = 10m and Width = 6m
(b.) Area = length x breadth (or width)
here we will use the special product (x+y) (x-y)
length = (x+y) and width = (x-y)
area = (8+2) x (8-2)
8^(2) - 2^(2)
= 60
Answer: x=-4.8
Step-by-step explanation:
Given
-10x+4=52
Subtract 4 on both sides
-10x+4-4=52-4
-10x=48
Divide -10 on both sides
-10x/-10=48/-10
x=-4.8
Hope this helps!! :)
Please let me know if you have any questions
Step-by-step explanation:
1kg=1000g
400kg=400*1000
=400000
Therefore 400kg =400000g
Data Set 1: (2, 2, 3, 4, 4, 5) Data Set 2: (5, 5, 10, 15, 15, 20) The difference between the interquartile ranges of the data se
vlabodo [156]
I R for data set 1 = 4-2 = 2
I R for data set2 = 15-5 = 10
Required difference is 10-2 = 8
Its 8.
The 4th one goes first. Then the 2nd one. After that the 1st one goes.
