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Mariulka [41]
3 years ago
12

Math help pls

Mathematics
2 answers:
dalvyx [7]3 years ago
5 0

Answer:

8 / 24

Step-by-step explanation:

VARVARA [1.3K]3 years ago
3 0

Answer:THIS TOOK ME FOREVER BUT WAS WORTH IT

1)1 1/7 times 1 3/4=2

2)8 1/3 times 3/5=5

3)4 3/8 times 1 2/3= 7 7/24

4)5 1/2 times 3 1/3=18 1/3

5)7 1/5 times 2 1/6=10 3/14

6)2/3 times 4/15=8/4

7)2 2/5 times 1 1.4=27 9/25

8)4 2/5 times 10=44

9)26 times 2 1/2=65

10)6 times 3 2/3=22

11)6 1/4 times 1 5/7=10 5/7

12)3 1/3 times 2 3/5=8 2/3

13)4 1/2 times 4 2/3=21

14)5 5/8 times 1 5/9=8 2/4

Step-by-step explanation:

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6 0
3 years ago
The period is.......
Leni [432]
<h3>Answer: 2.244 seconds</h3>

Explanation:

The x coordinate of the left peak point is x = 1.870, and its neighboring peak point has an x coordinate of x = 4.114

The difference is 4.114 - 1.870 = 2.244

The period is 2.244 seconds, which is the time it takes to go from one peak to another adjacent. This is the same as going from one valley point to a neighboring valley point.

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3 years ago
After 14 days how much homework was assign
san4es73 [151]

Answer:

none

Step-by-step explanation:

6 0
3 years ago
Which two sentences indicate a first-person point of view? 1 Shelley, our cat, always gets excited when Mrs. Peters visits us. 2
irga5000 [103]
The two sentences are 1 and 5.
3 0
3 years ago
In a survey, the planning value for the population proportion is p* = 0.35. How large a sample should be taken to provide a 95%
lions [1.4K]

Answer:

n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.59  

And rounded up we have that n=350  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p represent the real population proportion of interest

\aht p represent the estimated proportion for the sample

n is the sample size required (variable of interest)

z represent the critical value for the margin of error

Solution to the problem

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)

And replacing into equation (b) the values from part a we got:  

n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.59  

And rounded up we have that n=350  

6 0
2 years ago
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