Y = 16x^2 + 36 Lets find the intercepts, making x and y to zero and solving: <span>0 = 16x^2 + 36 </span><span>16x^2 = -36 </span>therefore there is not x-intercept, that is, when y equals zero the function does not have a value, is not defined. Now, the y intercept, that is when x equals zero: <span>y = 16x^2 + 36 </span><span>y = 16(0)^2 + 36 </span>y = 36 so, when x = 0, y = 36, that is, the function hits the y axis when x = 0
Ok so if we were to do the equation in real life, then it is not true since accorind to the equation, the apple goes higher as the time passses, therefor I conclude you forgot to include a (-) sign in front of the 16x^2 so therefor the true equation is y=-16x^2+36
x intercept is when the graph crosses the x axis or when y=0 y intercept is when the graph crosses the y axis or when x=0
so x intercept y=-16x^2+36 y=0 0=-16x^2+36 add 16x^2 to both sides 16x^2=36 divide both sides by 4 4x^2=9 divide both sides by 4 x^2=9/4 therefor x=-3/2 or 3/2 since x represents time and you cannot have negative time in real life, discard -3/2 x intercept=3/2 (times=3/2 seconds ie, the apple hits the ground at 3/2 seconds)
y intercept set x=0 y=-16(0)^2+36 y=36 y intercept=36 (this is the starting height of the apple)
