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3 years ago

How do you know which column is an input value?

Mathematics

1 answer:

Helen [10]3 years ago

8 0

Step-by-step explanation:

When we have a function in formula form, it is usually a simple matter to evaluate the function. For example, the function \displaystyle f\left(x\right)=5 - 3{x}^{2}f(x)=5−3x

can be evaluated by squaring the input value, multiplying by 3, and then subtracting the product from 5.

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Write -6 - 8i in polar form Appreciate any help thank you so much!

Temka [501]

-6 = r cos α and -8 = r sin α

r = sqrt( 6^2 + 8^2) = sqrt 100 = 10

α = arctan ( -8/-6) = arctan (4/3) = 53.13 degrees

polar firm = r ( cos α + i sin α)
= 10(cos 53.18 + i sin 53.18)

its been a long time but ui think thats correct

3 0

3 years ago

In a school, the ratio of teachers to girls is 1:7 while that of boys to girls is 3:4, If there are 280 girls in the school, wha

Nuetrik [128]

Answer:

The total number of pupils and their teachers = 530

Step-by-step explanation:

No. of girls in the school = 280

The ratio boys to girls is 3:4 and that of teachers to girls is 1:7

∴ The ratio boys to girls is 3x : 4x where, 4x = 280

and The ratio of teachers to girls is x : 7x where, 7x = 280

4x = 280

$\frac{280}{4\\}$ = x

70 = x

So, the no. of girls in the school = 4x = 4(70) = 280 and the no. of boys in the school = 3x = 3(70) = 210

7x = 280

$\frac{280}{7\\}$ = x

40 = x

So, the no. of girls in the school = 7x = 7(40) = 280 and the no. of teachers in the school = x = 40

∴ The total number of pupils and their teachers = 280 + 210 + 40

= 530

3 0

3 years ago

5.975 x 1024 plsss solve it

Mumz [18]

The answer will be 6118.4

4 0

3 years ago

Use the line plot below to determine the number of times less than 14 pieces of trash were collected at recess.

ICE Princess25 [194]

C. Which is 6. Hope this helps

3 0

2 years ago

Resolve the expression <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%28x-2%29%7D%7B%28x%5E%7B2%7D%20%2B1%29%28x-1%29%5E%7B2%7D%20

Llana [10]

The partial fraction expansion will look like

(x - 2)/((x ² + 1) (x - 1)²) = (ax + b)/(x ² + 1) + c/(x - 1) + d/(x - 1)²

Get everything in terms of a common denominator, and compare the numerators on both sides:

x - 2 = (ax + b) (x - 1)² + c (x ² + 1) (x - 1) + d (x ² + 1)

Expand the right side:

x - 2 = (ax + b) (x - 1)² + c (x ² + 1) (x - 1) + d (x ² + 1)

x - 2 = (a + c) x ³ + (-2a + b - c + d) x ² + (a - 2b + c) x + b - c + d

Match up the coefficients and solve the resulting system of equations:

a + c = 0

-2a + b - c + d = 0

a - 2b + c = 1

b - c + d = -2

==> a = -1, b = -1/2, c = 1, d = -1/2

So the expansion into partial fractions is

(x - 2)/((x ² + 1) (x - 1)²) = (-x - 1/2)/(x ² + 1) + 1/(x - 1) - 1/(2 (x - 1)²)

… = -(2x + 1)/(2 (x ² + 1)) + 1/(x - 1) - 1/(2 (x - 1)²)

5 0

3 years ago