Write -6 - 8i in polar form Appreciate any help thank you so much!

1 answer:

3 0

-6 = r cos α and -8 = r sin α

r = sqrt( 6^2 + 8^2) = sqrt 100 = 10

α = arctan ( -8/-6) = arctan (4/3) = 53.13 degrees

polar firm = r ( cos α + i sin α)
= 10(cos 53.18 + i sin 53.18)

its been a long time but ui think thats correct

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