5.975 x 1024 plsss solve it

Which function would be produced by a horizontal stretch of the of y=

sladkih [1.3K]

Answer: the answer to you question is c

3 0

3 years ago

Identify whether the following items best fit with a discrete or a continuous model. Then determine whether it is a linear (arit

astra-53 [7]

Answer:

it will be a continuous model

Step-by-step explanation:

weekend weekend assume every amount of area infected by the bed period doubles as hour passes

5 0

3 years ago

I need help with this

torisob [31]

Answer:

C(4, 6) => dilated by a factor of 1/3 => C'( 3x2/3, 6x2/3) = C'(2, 4)

3 0

3 years ago

The inside diameter of a randomly selected piston ring is a random variable with mean value 8 cm and standard deviation 0.03 cm.

S_A_V [24]

Answer:

a) P(7.99 ≤ X ≤ 8.01) = 0.8164

b) P(X ≥ 8.01) = 0.0475.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n can be approximated to a normal distribution with mean

In this problem, we have that:

$\mu = 8, \sigma = 0.03$

(a) Calculate P(7.99 ≤ X ≤ 8.01) when n = 16.

n = 16, so $s = \frac{0.03}{4} = 0.0075$

This probability is the pvalue of Z when X = 8.01 subtracted by the pvalue of Z when X = 7.99. So

X = 8.01

$Z = \frac{X - \mu}{\sigma}$

Applying the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.01 - 8}{0.0075}$

$Z = 1.33$

$Z = 1.33$ has a pvalue of 0.9082

X = 7.99

$Z = \frac{X - \mu}{s}$

$Z = \frac{7.99 - 8}{0.0075}$

$Z = -1.33$

$Z = -1.33$ has a pvalue of 0.0918

0.9082 - 0.0918 = 0.8164

P(7.99 ≤ X ≤ 8.01) = 0.8164

(b) How likely is it that the sample mean diameter exceeds 8.01 when n = 25? P(X ≥ 8.01) =

n = 25, so $s = \frac{0.03}{5} = 0.006$

This is 1 subtracted by the pvalue of Z when X = 8.01. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.01 - 8}{0.006}$

$Z = 1.67$

$Z = 1.67$ has a pvalue of 0.9525

1 - 0.9525 = 0.0475

P(X ≥ 8.01) = 0.0475.

4 0

3 years ago

Determine the number of outcomes in the event. Decide whether the event is a simple event or not. A computer is used to select r

Oliga [24]

The probability of selecting a number greater than 8 will be $p=\dfrac{1}{9}$ .

<h3>What is probability?</h3>

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

The number of outcomes = { 1,2,3,4,5,6,7,8,9 } = Counts = 9

Favourable outcomes = { 9 } = counts = 1

The probability will be given as:-

$P = \dfrac{1}{9}$

Therefore the probability of selecting a number greater than 8 will be $p=\dfrac{1}{9}$ .

To know more about probability follow

brainly.com/question/24756209

#SPJ1

7 0

2 years ago

5.975 x 1024 plsss solve it​

5.975 x 1024 plsss solve it