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3 years ago

Pls do it plz plz plz DO IT THE NOW!!!!

Mathematics

1 answer:

Zigmanuir [339]3 years ago

8 0

Answer:

(2 , 30) & (4, 60)

Step-by-step explanation:

y = 15x

When x = 2 , y = 15*2 = 30

When x = 4 ; y = 15 *4 = 60

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Give one example of when you would make a frequency table to solve the problem

RideAnS [48]

Answer:

Consider a class in which there are 40 students .There is a Mathematics test of 50 marks .Two students were absent.The Duration of test was for one and half an hour.

So Marks of students according to their roll number are 12,8,4,20,25,36,2,29,35,39,5,48,43,37,38,29,17,15,15,25,31,32,26,28,27,24,2,15,34,,50,46,48,37,28,26,45,49,24.

So in this case it would be better to prepare frequency polygon by selecting a class interval.

Class interval = 0-5,5-10,10-15,15-20,20-25,25-30,30-35,35-40,40-45,45-50.

Or 0-10,10-20,20-30,30-40,40-50.

or you can make class interval by yourself.

4 0

2 years ago

Find the value of x, please help!!!!

Fudgin [204]

Value of x is 77 degrees

4 0

3 years ago

Read 2 more answers

Give the inequality. PLEASE HELP ASAP, THANK YOU

Reil [10]

Answer:

$-3\le x\le 1$

$|x+1|\le2$

5 0

2 years ago

Find how many quarts of 6?% butterfat milk and 3?% butterfat milk should be mixed to yield 30 quarts of 5?% butterfat milk

Mrrafil [7]

Answer:

The 20 quarts are used for 6% butterfat milk and 10 quarts are used for 3% butterfat milk .

Step-by-step explanation:

As given

6% butterfat milk and 3% butterfat milk should be mixed to yield 30 quarts of 5% butterfat milk .

Let us assume that x quarts are used for 6% butterfat milk .

Than (30 - x) quarts are used for 3% butterfat milk .

6% is written in the decimal form

$= \frac{6}{100}$

= 0.06

3% is written in the decimal form

$= \frac{3}{100}$

= 0.03

5% is written in the decimal form

$= \frac{5}{100}$

= 0.05

Than the equation becomes

0.06 × x + (30 - x) × 0.03 = 30 × 0.05

0.06x + 0.9 - 0.03x = 1.5

0.06x - 0.03x = 1.5 - 0.9

0.03x = 0.6

$x = \frac{0.6}{0.03}$

x = 20 quarts for 6% butterfat milk .

(30 - x ) = (30 - 20) = 10 quarts for 3% butterfat milk .

Than 20 quarts are used for 6% butterfat milk and 10 quarts are used for 3% butterfat milk .

5 0

3 years ago

Please Please Please help with this math problem

katovenus [111]

The revenue as a function of x is equal to -x²/20 + 920x.
The profit as a function of x is equal to -x²/20 + 840x - 6000.
The value of x which maximizes profit is 8,400 and the maximum profit is $3,522,000.
The price to be charged to maximize profit is $500.

<h3>How to express the revenue as a function of x?</h3>

Based on the information provided, the cost function, C(x) is given by 80x + 6000 while the demand function, P(x) is given by -1/20(x) + 920.

Mathematically, the revenue can be calculated by using the following expression:

R(x) = x × P(x)

Revenue, R(x) = x(-1/20(x) + 920)

Revenue, R(x) = x(-x/20 + 920)

Revenue, R(x) = -x²/20 + 920x.

Expressing the profit as a function of x, we have:

Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = -x²/20 + 920x - (80x + 6000)

P(x) = -x²/20 + 840x - 6000.

For the value of x which maximizes profit, we would differentiate the profit function with respect to x:

P(x) = -x²/20 + 840x - 6000

P'(x) = -x/10 + 840

x/10 = 840

x = 840 × 10

x = 8,400.

For the maximum profit, we have:

P(x) = -x²/20 + 840x - 6000

P(8400) = -(8400)²/20 + 840(8400) - 6000

P(8400) = -3,528,000 + 7,056,000 - 6000

P(8400) = $3,522,000.

Lastly, we would calculate the price to be charged in order to maximize profit is given by:

P(x) = -1/20(x) + 920

P(x) = -1/20(8400) + 920

P(x) = -420 + 920

P(x) = $500.

Read more on maximized profit here: brainly.com/question/13800671

#SPJ1

3 0

1 year ago