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raketka [301]
2 years ago
15

Select all the correct answers. Function g is a transformation of the parent exponential function. Which statements are true abo

ut function g? A Linear graph function where red line g intercepts y-axis at (0, 4) and passes through (minus 10, 3) and (3, 10) Function g is positive over the interval . The domain of function g is . Function g has a y-intercept of . Function g decreasing over the interval . Function g is 4 units above function f. The range of function g is .
Mathematics
1 answer:
lesantik [10]2 years ago
5 0

The correct statements are:

Function g has a y-intercept of (0,4)

The range of the function g is (3, ∞).

The function g is positive over the interval (-∞ , ∞ ).

The parent function i.e. exponential function is defined by:

y=f(x)=aˣ

From the graph given below,

1. The graph of the function g is 3 units above the graph of the parent exponential function. as the parent exponential function aˣ cuts the y-axis at (0,1) and the child transformed function cut at (0,4) for which g is 4-1=3 units above the parent function  

2. The domain of the function is set of all the inputs for which function is defined. From the graph of function g, it is clear tha the domain of the function is (-∞ , ∞ ) as the domain of the parent exponential function is also (-∞ , ∞ ).

3. The y-intercept is the point at which function cut the y-axis. Graph of function g cut the y-axis at (0, 4). Therefore, Function g has the y-intercept at (0,4).

4. From the graph it is clear that Function g increases over the interval (-∞, 0) .

5. The range of the function is the output values of the function. From the graph, it is observed that the range of function g is (3, ∞). as its minimum value is 3 then the maximum value is ∞.

6. As, the graph of function g is drawn above the x-axis. Therefore, Function g lies completely on +ve y-axis, so function g is positive over the interval (-∞ , ∞ ).

Therefore The correct statements are:

Function g has a y-intercept of (0,4)

The range of the function g is (3, ∞).

The function g is positive over the interval (-∞ , ∞ ).

Learn more about the exponential function

here: brainly.com/question/2456547

#SPJ10

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Find the general solution of the equation: (y^2-2xy)dx + (2xy-x^2)dy = 0
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\dfrac{\partial(y^2-2xy)}{\partial y}=2y-2x

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f(x,y)=xy^2-x^2y+g(y)

Differentiating both sides wrt y gives

\dfrac{\partial f}{\partial y}=2xy-x^2+\dfrac{\mathrm dg}{\mathrm dy}=2xy-x^2

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Then the solution to the ODE is

f(x,y)=\boxed{xy^2-x^2y=C}

# # #

Alternatively, we can see that the ODE is homogeneous, since replacing x\to tx and y\to ty reduces to the same ODE:

((ty)^2-2(tx)(ty))\,\mathrm d(tx)+(2(tx)(ty)-(tx)^2)\,\mathrm d(ty)=0

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which is separable as

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-\dfrac13\ln|v(1-v)|=\ln|x|+C

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and solving in terms of y(x),

\dfrac yx\left(1-\dfrac yx\right)=\dfrac C{x^3}

xy(x-y)=C

\boxed{x^2y-xy^2=C}

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