How does the graph of y= sec(x-2)+2 comparé to the graph of y= sec(x) ?
2 answers:
Answer:
The function y= sec(x-2)+2 is shifted two units to the right and 2 units upwards., compared to y=sex(x).
Step-by-step explanation:
To solve this problem we need to know the rules for translation of graphs:
Given the function y = f(x):
- y=f(x-a) is the same graph shifted 'a' units to the right. If 'a' is negative, then, the graph is shifted to the left.
- y = f(x) - a is the same graph, but shifted 'a' units downwards. If 'a' is negative, then the graph will be shifted upwards.
In this case, our main function is y=sec(x). And the function y= sec(x-2)+2 is shifted two units to the right and 2 units upwards.
Answer:
D. it is shifted two units up and two units right
Step-by-step explanation:
this is the correct answer on ed-genuity, hope this helps! :)
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