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grin007 [14]
3 years ago
15

How does the graph of y= sec(x-2)+2 comparé to the graph of y= sec(x) ?

Mathematics
2 answers:
motikmotik3 years ago
8 0

Answer:

The function y= sec(x-2)+2 is shifted two units to the right and 2 units upwards., compared to y=sex(x).

Step-by-step explanation:

To solve this problem we need to know the rules for translation of graphs:

Given the function y = f(x):

  • y=f(x-a) is the same graph shifted 'a' units to the right. If 'a' is negative, then, the graph is shifted to the left.
  • y = f(x) - a is the same graph, but shifted 'a' units downwards. If 'a' is negative, then the graph will be shifted upwards.

In this case, our main function is y=sec(x). And the function y= sec(x-2)+2 is shifted two units to the right and 2 units upwards.

svetoff [14.1K]3 years ago
6 0

Answer:

D. it is shifted two units up and two units right

Step-by-step explanation:

this is the correct answer on ed-genuity, hope this helps! :)

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