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solniwko [45]
3 years ago
11

What is simplified form of the fifth square root of x times the fifth square root of x times the fifth square root of x times th

e fifth square root of x
Mathematics
2 answers:
Gala2k [10]3 years ago
8 0

Answer:

x

Step-by-step explanation:

Apply exponent rules.

\sqrt{x} =x^\frac{1}{2}\\\:a^b\times \:a^c=a^{b+c}

\sqrt[5]{x} \times\sqrt[5]{x} \times\sqrt[5]{x} \times\sqrt[5]{x} \times\sqrt[5]{x}

x^{\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}}

x^1

Radda [10]3 years ago
7 0

Answer: This was a bit hard to understand, x times the 5th root of x

Step-by-step explanation:

When you multiply square roots of the same root and inside value, they essentially get rid of the square roots. So the first two terms boil down to just x. Then multiply x by the 5th root of x to get:

x\sqrt[5]{x}

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Looks like you are missing a fraction after the 'If'
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When a question ask you to describe the relationship what does that mean and how will u do it
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In this case you can say in one hour Austin earns $7.50.

4 0
2 years ago
Enny White is shopping for CDs. She decides to purchase 3 movie soundtracks. The music store has 7 different movie soundtracks i
zubka84 [21]

Answer:

35\ ways

Step-by-step explanation:

we know that

<u><em>Combinations</em></u> are a way to calculate the total outcomes of an event where order of the outcomes does not matter.

To calculate combinations, we will use the formula

C(n,r)=\frac{n!}{r!(n-r)!}

where

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r represents the number of items being chosen at a time.

In this problem

n=7\\r=3

substitute

C(7,3)=\frac{7!}{3!(7-3)!}\\\\C(7,3)=\frac{7!}{3!(4)!}

simplify

C(7,3)=\frac{(7)(6)(5)4!}{3!(4)!}

C(7,3)=\frac{(7)(6)(5)}{3!}

C(7,3)=\frac{(7)(6)(5)}{(3)(2)(1)}

C(7,3)=35\ ways

6 0
3 years ago
A sprinter can run 279 feet in 9 seconds. find the sprinter's unit rate of feet per second.
MariettaO [177]
279ft/9sec = xft/1sec
Cross multiply to get
9x = 279 divide by 9
x = 31
31 feet per second
3 0
3 years ago
Read 2 more answers
the initial term of arithmetic sequence is 5. The eleventh term is 125. what is the common difference of the arithmetic sequence
kap26 [50]
An arithmetic sequence starts with one number and you add the common difference to the previous term to get the current term
So...
f(x)=mx+b
m=common difference
b=starting point
f(11)=125=11m+b
-
f(1)=5=1m+b
--------
120=10m
Divide both sides by 10
12=m
Your common difference is 12.



4 0
2 years ago
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