Question

X² + 3x -4 = 0 Factor the quadratic equation

Answer 1

Answer:

(x-1)(x+4)

Step-by-step explanation:

$x^2+3x-4\\x^2-x+4x-4\\x(x-1) 4(x-1)\\(x-1)(x+4)$

Answer 2

(x+4)(x-1)

First, find the factors of the constant (number without an x)

The factors of -4 are:
-1, 4
1, -4
2, -2

Looking at these factors find which pair of factors adds up to the middle number (3x)

4 + -1 = 3

Now you can factor this equation. Put x + 4 into one pair of parenthesis and x - 1 into another pair of parenthesis. You do this because you are separating the two factors into two expressions, that when multiplied together, will equal x^2 + 3x - 4

(x+4)(x-1) is the answer

To check this, multiply the two expressions together. You should get x^2+3x-4=0