Hi Timothy,
1. Write a rule for the sequence.
8, -1, -10, -19...
A. Start with 8 and add -9 repeatedly
B. star with -9 and add 8 repeatedly
C. start with 8 and add 9 repeatedly
D. start with 8 and subtract -9 repeatedly---
Answer - So you have to start with -9 then keep subtracting 9. Thats what I think the answer is but the answer is not stated in the question. Let me know on what that is. The closest answer is probably either B or D.
2. find the next three terms of the sequence.
-6, -24, -96, -384
1) -768, -1536 , -3072
2) -768, -3072, -12288
3) -1536, -6144 , -24567
4) -1536, -9216, -36864
The rule is multiplying by 4!
So the correct answer is 3) -1536, -6144 , -24567
Answer:
since equation 1 says that X= 1
any other equation saying x=1 will be valid!
Equation A
Equation B
Equation C
Equation D
all correct
Answer:
.216
Step-by-step explanation:
I think you're asking for a numerical answer, but you didn't mention
your score on the final.
Since the final is worth 10% (one tenth) of the grade, that 71 that you
have going into the final is worth 9/10 of the grade. So the way you
calculate your overall average is
Overall score = 1/10 of [ (71 x 9) + score on the final ] .
If you scored absolute zero on the final, your overall average would be
Overall score = (1/10) x [ (71 x 9) + 0 ] = (1/10) (639) = <u>63.9%</u> .
That's the lowest overall score for the class that you can have.
The <u>highest</u> overall score you could have would be if you got 100% on the final.
Then
Overall = (1/10) x (639 + 100) = (1/10) x (739) = <u>73.9%</u> .
If you got a 50% on the final, your overall would be
(1/10) x (639 + 50) = (1/10) x (689) = <u>68.9%</u> .
In general, your overall score for the class, after the final, is going to be
63.9% plus (1 tenth) of your score on the final.
Good luck !
