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NikAS [45]
3 years ago
9

The population of deer in a state park can be predicted by the expression 106(1.087)t, where t is the number of years since 2010

.
Mathematics
1 answer:
Arturiano [62]3 years ago
8 0

Answer:

b) When will the number of deer be 600?

Step-by-step explanation:

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Plz someone explain it
Savatey [412]

Answer:

-4(8)=x^2-9x+12

-32=x^2-9x+12

Step-by-step explanation: is this what u want us to do?

8 0
2 years ago
What steps would you take to determine if these figures are similar? Check all that apply. Use a scale factor of 2. Multiply the
skad [1K]

Answer:

Well I took it"s Reflect the intermediate image.  and Multiply the vertices of polygon ABCD by One-half.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Indicate the equation of the given line in standard form.
Lorico [155]
We have that
<span>triangle ABC
where
A(-5, 5), B(1, 1), and C(3, 4) are the vertices

using a graph tool
see the attached figure

the hypotenuse is the segment AC

find the equation of the line AC
</span>A(-5, 5) C(3, 4) 
<span>
step 1
find the slope m
m=(y2-y1)/(x2-x1)-----> m=</span>(4-5)/(3+5)-----> m=-1/8

step 2
with C(3,4) and m=-1/8
find the equation of a line
y-y1=m*(x-x1)-----> y-4=(-1/8)*(x-3)----> y=(-1/8)*x+(3/8)+4
y=(-1/8)*x+(3/8)+4----> multiply by 8----> 8y=-x+3+32
8y=-x+35
the standard form is Ax+By=C
so
x+8y=35
A=1
B=8
C=35

the answer is
x+8y=35


7 0
3 years ago
An athlete knows that when she jogs along her neighborhood​ greenway, she can complete the route in 10 minutes. It takes 20 minu
IgorLugansk [536]

Answer:

10 miles per hour.

Step-by-step explanation:

Let x represent athlete's walking speed.

We have been given that her jogging rate is 5 mph faster than her walking​ rate, so athlete's jogging speed would be x+5 miles per hour.

\text{Distance}=\text{Rate}\cdot \text{Time}

10 minutes = 1/6 hour.

20 minutes = 1/3 hour

While walking, we will get D_{\text{walking}}=x\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{3}\text{hour}

D_{\text{walking}}=\frac{x}{3}

While jogging, we will get D_{\text{jogging}}=(x+5)\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{6}\text{hour}

D_{\text{jogging}}= \frac{(x+5)}{6}

Since athlete is covering same distance while walking and jogging, so we can equate both expressions as:

\frac{x}{3}=\frac{x+5}{6}

Cross multiply:

6x=3x+15

6x-3x=15

3x=15

\frac{3x}{3}=\frac{15}{3}\\\\x=5

Therefore, athlete's walking speed is 5 miles per hour.

Jogging speed: x+5\Rightarrow 5+5=10

Therefore, athlete's jogging speed is 10 miles per hour.

3 0
3 years ago
How do you calculate this?
Dmitry_Shevchenko [17]

d = 5.6t {}^{2}  \\ 1814.4 = 5.6 \times t {}^{2}  \\ t {}^{2}  = 1814.4 \div 5.6 \\ t {}^{2}  = 324 \\ t =  \sqrt{324}  \\ t = 18
7 0
3 years ago
Read 2 more answers
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