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Nataly_w [17]
3 years ago
9

An athlete knows that when she jogs along her neighborhood​ greenway, she can complete the route in 10 minutes. It takes 20 minu

tes to cover the same distance when she walks. If her jogging rate is 5 mph faster than her walking​ rate, find the speed at which she jogs.
Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

10 miles per hour.

Step-by-step explanation:

Let x represent athlete's walking speed.

We have been given that her jogging rate is 5 mph faster than her walking​ rate, so athlete's jogging speed would be x+5 miles per hour.

\text{Distance}=\text{Rate}\cdot \text{Time}

10 minutes = 1/6 hour.

20 minutes = 1/3 hour

While walking, we will get D_{\text{walking}}=x\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{3}\text{hour}

D_{\text{walking}}=\frac{x}{3}

While jogging, we will get D_{\text{jogging}}=(x+5)\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{6}\text{hour}

D_{\text{jogging}}= \frac{(x+5)}{6}

Since athlete is covering same distance while walking and jogging, so we can equate both expressions as:

\frac{x}{3}=\frac{x+5}{6}

Cross multiply:

6x=3x+15

6x-3x=15

3x=15

\frac{3x}{3}=\frac{15}{3}\\\\x=5

Therefore, athlete's walking speed is 5 miles per hour.

Jogging speed: x+5\Rightarrow 5+5=10

Therefore, athlete's jogging speed is 10 miles per hour.

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Answer:

f(4)=26

Step-by-step explanation:

f(2)=16

F(x) = kx+6

16=k(2)+6

16-6=k(2)

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2 2

5= k

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5 0
2 years ago
Prudence has 12 pairs of gold earrings and 12 pairs of silver earrings in a drawer in her jewelry box. If she randomly pulls six
algol13

Answer:

(D) 3

Step-by-step explanation:

Prudence has 12 pairs of gold earrings and 12 pairs of silver earrings.

Total Number of Earrings =12+12=24

Relative Frequency of Picking a Gold Earrings =12/24= 0.5

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7 0
3 years ago
Find the work done in winding up a 175 ft cable that weighs 3 lb/ft.
nignag [31]

Answer:

work \ done= 45937.5

Step-by-step explanation:

Work done is given by

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Here, d = 175 ft and w = 3 lb/ft

Now, work \ done=\int_0^{175} 3(175-x) \ dx

work \ done= 3\left [175x-\frac{x^2}{2}  \right ]_0^{175}

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work \ done= 3\cdot \frac{175^2}{2}

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What is the value of the expression?<br><br> 53/5+7/10−22/3
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cluponka [151]

Answer:

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Step-by-step explanation:

Each year, the amount Walter owes is multiplied by 1.06, so at the end of 6 years, Walter owes 1.06^6 times the amount he borrowed.

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At the end of the first year, Walter owes the original loan amount plus 6% interest. That total is ...

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At the end of the following year, he owes 1.06 times that amount, or ...

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The amount owed is multiplied by 1.06 each year until Walter pays off the loan.

8 0
3 years ago
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