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Nataly_w [17]
4 years ago
9

An athlete knows that when she jogs along her neighborhood​ greenway, she can complete the route in 10 minutes. It takes 20 minu

tes to cover the same distance when she walks. If her jogging rate is 5 mph faster than her walking​ rate, find the speed at which she jogs.
Mathematics
1 answer:
IgorLugansk [536]4 years ago
3 0

Answer:

10 miles per hour.

Step-by-step explanation:

Let x represent athlete's walking speed.

We have been given that her jogging rate is 5 mph faster than her walking​ rate, so athlete's jogging speed would be x+5 miles per hour.

\text{Distance}=\text{Rate}\cdot \text{Time}

10 minutes = 1/6 hour.

20 minutes = 1/3 hour

While walking, we will get D_{\text{walking}}=x\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{3}\text{hour}

D_{\text{walking}}=\frac{x}{3}

While jogging, we will get D_{\text{jogging}}=(x+5)\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{6}\text{hour}

D_{\text{jogging}}= \frac{(x+5)}{6}

Since athlete is covering same distance while walking and jogging, so we can equate both expressions as:

\frac{x}{3}=\frac{x+5}{6}

Cross multiply:

6x=3x+15

6x-3x=15

3x=15

\frac{3x}{3}=\frac{15}{3}\\\\x=5

Therefore, athlete's walking speed is 5 miles per hour.

Jogging speed: x+5\Rightarrow 5+5=10

Therefore, athlete's jogging speed is 10 miles per hour.

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The manager of a music store has kept records of
Marysya12 [62]

Answer:

(a) P(x\le 3) = 0.75

(b) P(x\le 3) = 0.75

<em>(b) is the same as (a)</em>

(c) P(x \ge 5) = 0.10

(d) P(x = 1\ or\ 2) = 0.55

(e) P(x > 2) = 0.45

Step-by-step explanation:

Given

\begin{array}{ccccccc}{CDs} & {1} & {2} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.30} & {0.25} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}

Solving (a): Probability of 3 or fewer CDs

Here, we consider:

\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}

This probability is calculated as:

P(x\le 3) = P(1) + P(2) + P(3)

This gives:

P(x\le 3) = 0.30 + 0.25 + 0.20

P(x\le 3) = 0.75

Solving (b): Probability of at most 3 CDs

Here, we consider:

\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}

This probability is calculated as:

P(x\le 3) = P(1) + P(2) + P(3)

This gives:

P(x\le 3) = 0.30 + 0.25 + 0.20

P(x\le 3) = 0.75

<em>(b) is the same as (a)</em>

<em />

Solving (c): Probability of 5 or more CDs

Here, we consider:

\begin{array}{ccc}{CDs} & {5} & {6\ or\ more}\ \\ {Prob} & {0.05} & {0.05}\ \ \end{array}

This probability is calculated as:

P(x \ge 5) = P(5) + P(6\ or\ more)

This gives:

P(x\ge 5) = 0.05 + 0.05

P(x \ge 5) = 0.10

Solving (d): Probability of 1 or 2 CDs

Here, we consider:

\begin{array}{ccc}{CDs} & {1} & {2} \ \\ {Prob} & {0.30} & {0.25} \ \ \end{array}

This probability is calculated as:

P(x = 1\ or\ 2) = P(1) + P(2)

This gives:

P(x = 1\ or\ 2) = 0.30 + 0.25

P(x = 1\ or\ 2) = 0.55

Solving (e): Probability of more than 2 CDs

Here, we consider:

\begin{array}{ccccc}{CDs} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}

This probability is calculated as:

P(x > 2) = P(3) + P(4) + P(5) + P(6\ or\ more)

This gives:

P(x > 2) = 0.20+ 0.15 + 0.05 + 0.05

P(x > 2) = 0.45

3 0
3 years ago
An evaluation of the habitats of endangered salmon species was performed in Conservation Ecology (December 2003). The researcher
adell [148]

Answer: The habitat quality score will be normally distributed if at least 50% of the total sites are captured

Step-by-step explanation:

5 0
3 years ago
Can someone help me ASAP
nalin [4]
#2 is C because you are looking at the Y-axis and i don't know if you needed help for #3 but if you did I can't see the question.
8 0
3 years ago
Connie Harris, in charge of office supplies at First Capital Mortgage Corp., would like to predict the quantity of paper used in
Amiraneli [1.4K]

Answer:

y = 0.325X + 7.5 ;

21.5 ;

R^2 = 0.7655 ;

r = 0.8749

Step-by-step explanation:

No. of loans originated ____ sheets of p/paper

45 ______________22

25 ______________ 13

50 _____________ 24

60 _____________ 25

40 _____________ 21

25 _____________ 16

35 _____________ 18

40 _____________ 25

Using the linear regression calculator : the linear model obtained is:

y = 0.325X + 7.5

y = predicted variable = sheets of photocopy paper

X = number of loans originated

0.325 = slope

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B.)

X = 42

y = 0.325(42) + 7.5

y = 21.15

C.)

The Coefficient of determination as determined using the correlation coefficient calculator is :

R^2 = 0.7655 ; this means that about 76.55% of change in number of photocopy performed is explained by the number of loans originated.

D.) The correlation Coefficient (r) :

r = sqrt(R²)

r = sqrt(0.7655)

r = 0.8749

This shows that a strong positive correlation exists between the number of loans originated and the volume of photocopying done.

3 0
3 years ago
May I please get help with this. For I am confused as I have tried multiple times to get the correct answers but still could not
Goshia [24]

ANSWER

10.18

EXPLANATION

We want to approximate, using the ALEKS calculator, the value of:

\sqrt[]{103.7}

To do this, we input the radical and the number into the calculator. The result is:

10.18331969

Since we have to round the answer to the nearest hundredth, we will pick the number in the thousandths place value, which is 3.

This number is less than 5, so, we round it down to 0 and add it to the number in the hundredth place value, which is 8.

Hence, the answer is:

10.18

6 0
1 year ago
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