Answer:
f(4)=26
Step-by-step explanation:
f(2)=16
F(x) = kx+6
16=k(2)+6
16-6=k(2)
10=k(2)
<u>10</u> =<u>k(</u><u>2</u><u>)</u>
2 2
5= k
f(4)=k(4)+6
=5(4)+6
=20+6
f(4)=26
Answer:
(D) 3
Step-by-step explanation:
Prudence has 12 pairs of gold earrings and 12 pairs of silver earrings.
Total Number of Earrings =12+12=24
Relative Frequency of Picking a Gold Earrings =12/24= 0.5
If she randomly pulls six pairs of earrings out of the drawer to take with her on a trip
Number of Possible Outcome =Relative Frequency X Number of Trials
=0.5 X 6
=3
She would most likely take 3 gold earrings.
Answer:

Step-by-step explanation:
Work done is given by
, where d = length of cable and w = weight of cable.
Here, d = 175 ft and w = 3 lb/ft
Now, 
![work \ done= 3\left [175x-\frac{x^2}{2} \right ]_0^{175}](https://tex.z-dn.net/?f=work%20%5C%20done%3D%203%5Cleft%20%5B175x-%5Cfrac%7Bx%5E2%7D%7B2%7D%20%20%5Cright%20%5D_0%5E%7B175%7D)
![work \ done= 3\left [175^2-\frac{175^2}{2} \right ]](https://tex.z-dn.net/?f=work%20%5C%20done%3D%203%5Cleft%20%5B175%5E2-%5Cfrac%7B175%5E2%7D%7B2%7D%20%20%5Cright%20%5D)


119/30 or 3.96 or 3 29/30
Explanation:
First write all numerators above the least common denominator (in this case 30)
Then calculate the sum or difference
Answer:
$8511.11
Step-by-step explanation:
Each year, the amount Walter owes is multiplied by 1.06, so at the end of 6 years, Walter owes 1.06^6 times the amount he borrowed.
he will pay $6,000×1.06^6 ≈ $8511.11
_____
At the end of the first year, Walter owes the original loan amount plus 6% interest. That total is ...
$6000 + 0.06×6000 = $6000×1.06
At the end of the following year, he owes 1.06 times that amount, or ...
6000×1.06²
The amount owed is multiplied by 1.06 each year until Walter pays off the loan.