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just olya [345]
2 years ago
7

6th grade math i mark as brainliest​

Mathematics
1 answer:
CaHeK987 [17]2 years ago
5 0
The answer would be C, sorry if I’m wrong
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Beth estimates her expenditures for transportation as follows: May, $91; June, $122; July $478. What is her estimated average mo
kipiarov [429]

Answer:

around 230

Step-by-step explanation:

91+122+478=691

691÷3= 230.33333333

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Montel spends $0.75 every time he plays his favorite video game. If you have $10, write and resolve an inequality to calculate h
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the answer is the last one

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On Tuesday morning, the temperature was recorded
VashaNatasha [74]
C. -2° :) hope this helps lmk!
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3 years ago
Suppose each edge of the cube shown in the figure is 10 inches long. Find the sine and cosine of the angle formed by diagonals D
tatiyna

Check the picture below.

sin(EDG )=\cfrac{\stackrel{opposite}{10}}{\underset{hypotenuse}{10\sqrt{3}}}\implies sin(EDG )=\cfrac{1}{\sqrt{3}}\implies sin(EDG )=\cfrac{1}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{sin(EDG )=\cfrac{\sqrt{3}}{\sqrt{3^2}}\implies sin(EDG )=\cfrac{\sqrt{3}}{3}} \\\\[-0.35em] ~\dotfill

cos(EDG )=\cfrac{\stackrel{adjacent}{10\sqrt{2}}}{\underset{hypotenuse}{10\sqrt{3}}}\implies cos(EDG )=\cfrac{\sqrt{2}}{\sqrt{3}}\implies cos(EDG )=\cfrac{\sqrt{2}}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{cos(EDG )=\cfrac{\sqrt{6}}{\sqrt{3^2}}\implies cos(EDG )=\cfrac{\sqrt{6}}{3}}

4 0
2 years ago
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